I have following code, but I want to change the variable of p, how can I do it? {p(1;2;3;4)}. :- p(X*2). It is normal. But the following code does'nt work. p(1
I have following code, but I want to change the variable of p, how can I do it? {p(1;2;3;4)}. :- p(X*2). It is normal. But the following code does'nt work. p(1
I have the following code: 1{p(1..10)}10. :- p(I*2). and it shows 31 answers, But I just need the max subset p(1) p(3) p(5) p(7) p(9). How can I do it?
I wrote an algorithm in answer set programming, run with clingo, to calculate a league of 20 teams and its 38 matches (19 round and 19 return) with certain cons