A basic C++ recursion question I can't wrap my head around

Question

I am learning the basics of CPP programming. I came across this basic recursion question which I'm unable to understand. The output is 1 2 3 4 5 but I don't understand why.

At the first iteration (f(5)), we get into the if condition and call f(5-1). Won't calling f(5-1) here (before cout) take us back to the f(int n) function and skip printing anything at all. Even if we do go to cout after f(5-1), won't cout display 5 instead of 1 for the first iteration? Here is the code. Thank you!

    #include <iostream>
    using namespace std;
    void f(int n)
    {
      if (n > 0)
      {
        f(n - 1);
        cout << n << " ";
      }
    }
    int main()
    {
      f(5);
      return 0;
    }