'add " ? " in url via htaccess RewriteRule
i try use RewriteRule in htaccess
i want my url
site.com/f_search.php?langs=en&langs=en
works like
site.com/en/new.php?/en/f_search
i used this code in htaccess
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^([^/]*)/?/new.php+?+/([^/]*)/?/f_search/?$ f_search.php?langs=$1&langs=$2
but its not work with " ? "
if i change new.php+?+ to new.php+@+
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^([^/]*)/?/new.php+@+/([^/]*)/?/f_search/?$ f_search.php?langs=$1&langs=$2
it works good
site.com/en/new.php@/en/f_search
any idea to change @ to ? in my url ???
thanks
Solution 1:[1]
The question mark and what follows is not part of the subject the pattern of a RewriteRule is matched against. That is clearly documented. Instead you need to use a RewriteCond
to access the content of the query string.
I assume this is roughly what you are looking for, though you might have to tweak it to match your actual situation:
RewriteEngine on
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{QUERY_STRING} ^/([a-z]+)/f_search$
RewriteRule ^/?(?:([a-z]+)/)?new\.php$ /f_search.php?langs=$1&langs=%1
From your question it is unclear where the two values for the argument "langs" in the rewrite target should get taken. So you may have to adjust that to your needs in the rule.
Also it is puzzling that you are trying to set that argument "langs" twice ... That makes little sense, the second attempt will simply overwrite the value of the first attempt when those values are handed over to your php based logic.
The documentation of the rewriting module for the apache http server offer a lot of precise help and good examples: https://httpd.apache.org/docs/current/mod/mod_rewrite.html
Solution 2:[2]
the final code
RewriteEngine on
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^/?([a-z]+)/new.php$ f_search.php?langs=$1 [L,NC]
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | new developer |