'Angular 2: Get position of HTML element

I'm trying to implement a custom directive in Angular 2 for moving an arbitrary HTML element around. So far everything is working except that I don't now how to get the initial position of the HTML element when I click on it and want to start moving. I'm binding to the top and left styles of my HTML element with those two host bindings:

/** current Y position of the native element. */
@HostBinding('style.top.px') public positionTop: number;

/** current X position of the native element. */
@HostBinding('style.left.px') protected positionLeft: number;

The problem is that both of them are undefined at the beginning. I can only update the values which will also update the HTML element but I cannot read it? Is that suppose to be that way? And if yes what alternative do I have to retrieve the current position of the HTML element.



Solution 1:[1]

<div (click)="move()">xxx</div>
// get the host element
constructor(elRef:ElementRef) {}

move(ref: ElementRef) {
  console.log(this.elRef.nativeElement.offsetLeft);
}

See also https://stackoverflow.com/a/39149560/217408

Solution 2:[2]

In typeScript you can get the position as follows:

@ViewChild('ElementRefName') element: ElementRef;

const {x, y} = this.element.nativeElement.getBoundingClientRect();

Solution 3:[3]

in html:

<div (click)="getPosition($event)">xxx</div>

in typescript:

getPosition(event){
    let offsetLeft = 0;
    let offsetTop = 0;

    let el = event.srcElement;

    while(el){
        offsetLeft += el.offsetLeft;
        offsetTop += el.offsetTop;
        el = el.parentElement;
    }
    return { offsetTop:offsetTop , offsetLeft:offsetLeft }
}

Solution 4:[4]

You can use two way

// html

<div id="section" ></div>

// 1)

@ViewChild('section', { static: false }) public section?: ElementRef;

this.section.nativeElement.scrollIntoView({ behavior: "smooth", block: "start" });

// 2)

document.getElementById("section").scrollIntoView({ behavior: "smooth", block: "center" });

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Community
Solution 2 William Perez Herrera
Solution 3 mohammad ali
Solution 4