'Auto increment table column
Using Postgres, I'm trying to use AUTO_INCREMENT
to number my primary key automatically in SQL. However, it gives me an error.
CREATE TABLE Staff (
ID INTEGER NOT NULL AUTO_INCREMENT,
Name VARCHAR(40) NOT NULL,
PRIMARY KEY (ID)
);
The error:
********** Error ********** ERROR: syntax error at or near "AUTO_INCREMENT" SQL state: 42601 Character: 63
Any idea why?
Solution 1:[1]
Postgres 10 or later
(serial
columns remain unchanged, see below.)
Consider a standard-SQL IDENTITY
column. Can be GENERATED BY DEFAULT
or (stricter) GENERATED ALWAYS
.
Basics in the manual for CREATE TABLE
.
Details in this blog entry by its principal author Peter Eisentraut.
Create table with IDENTITY
column
CREATE TABLE staff (
staff_id int GENERATED ALWAYS AS IDENTITY PRIMARY KEY
, staff text NOT NULL
);
Add IDENTITY
column to existing table
Table may or may not be populated with rows.
ALTER TABLE staff ADD COLUMN staff_id int GENERATED ALWAYS AS IDENTITY;
To also make it the PK at the same time (table can't have a PK yet):
ALTER TABLE staff ADD COLUMN staff_id int GENERATED ALWAYS AS IDENTITY PRIMARY KEY;
See:
Replace serial
with IDENTITY
column
See:
You can override system values or user input in INSERT
commands with OVERRIDING {SYSTEM|USER} VALUE
.
Postgres 9.6 or older
(Still supported in newer versions, too.)
Use the serial
pseudo data type:
CREATE TABLE staff (
staff_id serial PRIMARY KEY,
, staff text NOT NULL
);
It creates and attaches the sequence object automatically and sets the DEFAULT
to nextval()
from the sequence. It does all you need.
I use legal, lower-case, unquoted identifiers in my examples. Makes your life with Postgres easier.
Solution 2:[2]
You do not specify which RDBMS you are using, however, in SQL Server you can use this syntax:
CREATE TABLE [dbo].[Staff]
(
[ID] [int] IDENTITY(1,1) NOT NULL,
[Name] VARCHAR(40) NOT NULL,
CONSTRAINT [ID] PRIMARY KEY CLUSTERED
(
[ID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
Solution 3:[3]
In the SQL server database you can use Identity(1,1)
like this:
CREATE TABLE Staff
(
ID INT IDENTITY(1,1) NOT NULL,
Name VARCHAR(40) NOT NULL,
PRIMARY KEY (ID)
);
Solution 4:[4]
PostgreSQL: If you absolutely must have your own auto increment value:
Then use a sequence:
ericlesc_schools=> drop table yar;
DROP TABLE
ericlesc_schools=> drop sequence user_id_seq;
DROP SEQUENCE
ericlesc_schools=> create sequence user_id_seq;
CREATE SEQUENCE
ericlesc_schools=> create table yar(
id int default nextval('user_id_seq'),
foobar varchar);
CREATE TABLE
ericlesc_schools=> insert into yar (foobar) values('hey alex');
INSERT 0 1
ericlesc_schools=> insert into yar (foobar) values('hey what derick');
INSERT 0 1
ericlesc_schools=> insert into yar (foobar) values('I look like a hushpuppy');
INSERT 0 1
ericlesc_schools=> select * from yar;
id | foobar
----+-----------------
1 | hey alex
2 | hey what derick
3 | I look like a hushpuppy
(3 rows)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | Barry Kaye |
Solution 3 | Eric Leschinski |
Solution 4 | Eric Leschinski |