Capitalize First Letter of Every Word inside Bracket

Question

I'm trying to write some useful Regex for Tagscanner (a music tagger on Windows) and spent a bunch of time on regex101.com to fulfill my idea.

In some language like French, it's a huge pain to make the title look good if you capitalize every word. I just want to capitalize the first letter of every word in round bracket. I will receive the string like this :

Edith Piaf - La vie en rose (louis armstrong 2015 version)

I started with this base :

/([a-z])([\w-']*)([\s\)\]\,;\d]*|$)/gi
that I replace by \U\1\E\2\3

([a-z]) I try to capture the letter I want in uppercase
([\w-']*) What I expect to be the rest of the word
([\s\)\]\,;\d]|$) Delimiters

This will actually Capitalize everywhere correctly in the title, then the problems come...

I tried to ignore everything until I encounter '('

\(\K or \({1} or with \(\A or \((*SKIP) etc...

Positive lookbehind (?<=() doesn't work either because after my first match it will look if I have '(' again.

Also tried to capture the whole thing and put * after doesn't work either.

I just don't know how to do it. Thank you very much for helping!

Answer 1

With Perl's rename from @Wiktor Stribi?ew's regex:

rename -n 's/(?:\G(?!^)|\()[^()]*?\K\b(\p{Ll})(\w*)/\U$1\E$2/gmu'  Edith*

Remove -n switch when the output looks good.

There are other tools with the same name which may or may not be able to do this, so be careful.

cpan standalone script