I am trying to build a site where I can upload multiple images with php and mysql but I am getting below error: Fatal error: Uncaught ArgumentCountError: mysql
i am creating php script to take input from a data base containing [id,value,date] , there are many rows (increasing every minute using an api
Hi everyone please i need you're help. What i want is when the input field is updated with this value: Résolu --> update column date with date now. I
I need to execute two or more queries at a time, fetch them one after another. Then I need to bind param and bind result in each one of them. I am trying this
I have a problem with passing the query that returns a number of records, I already have it with a select that returns an input, but this only works with one re
I have a search engine that I found on google and I would like to search in the 'barcode' database that I have and if it finds the person it executes the code t
My code against SQL injection isn't working (error message in title). I simplified my code, but its still not working. <?php include "con
my connection: $con = new mysqli('localhost', 'root', '', 'test'); it does not work with that either: $con = new mysqli('localhost', 'root', '', 'test'
I have an issue when I clicked the button and submit the data from the form.it gets directly to the white screen and nothing happen I checked the database it do
I keep getting the following errors with mysql connection through XAMPP and I don't know what to do: That's the code in the config.inc.php <?php /* * Th
I am trying to do a simple test but am experiencing errors. I am trying to add the parameters and I have done some research, none of which has helped me underst
i'm trying to learn mysqli. i get this error: Fatal error: Uncaught Error: Call to undefined method mysqli_stmt::fetch_assoc() in C:\xampp\h
This does not work $sql = 'SELECT * FROM `users` WHERE username LIKE \'%{?}%\' '; Warning: mysqli_stmt::bind_param(): Number of variables doesn't match numbe
I have ubuntu 14.04 EC2 instance. I have installed php 7 on it. when I execute any php command like php --version or any other. I get following error PHP Warni
Hi i cant use INSERT UPDATE function with this class: MySQLiDB. Im trying write data to mysql and if exists this data then need update. So i use INSERT ... ON D
For my PHP I get a warning message: Warning: mysqli_result::fetch_array(): Couldn't fetch mysqli_result in /var/www/scorebord/loader.php on l
Is it better to open and close a new MySQL connection every time a query is made or to keep the connection open and run multiple queries in a single MySQL sessi
Is it better to open and close a new MySQL connection every time a query is made or to keep the connection open and run multiple queries in a single MySQL sessi
I try to perform this query with Zend DB: $this->db->query(" CREATE EVENT turn_tonormal ON SCHEDULE AT CURRENT_TIMESTAMP + INTERVA
So my goal is to output some mysql info to a table. I want it to start a new column every 18th record. Here is my current code: $hostname = "localhost"; //SET