'Change a Django form field to a hidden field
I have a Django form with a RegexField
, which is very similar to a normal text input field.
In my view, under certain conditions I want to hide it from the user, and trying to keep the form as similar as possible. What's the best way to turn this field into a HiddenInput
field?
I know I can set attributes on the field with:
form['fieldname'].field.widget.attr['readonly'] = 'readonly'
And I can set the desired initial value with:
form.initial['fieldname'] = 'mydesiredvalue'
However, that won't change the form of the widget.
What's the best / most "django-y" / least "hacky" way to make this field a <input type="hidden">
field?
Solution 1:[1]
If you have a custom template and view you may exclude the field and use {{ modelform.instance.field }}
to get the value.
also you may prefer to use in the view:
form.fields['field_name'].widget = forms.HiddenInput()
but I'm not sure it will protect save method on post.
Hope it helps.
Solution 2:[2]
This may also be useful: {{ form.field.as_hidden }}
Solution 3:[3]
an option that worked for me, define the field in the original form as:
forms.CharField(widget = forms.HiddenInput(), required = False)
then when you override it in the new Class it will keep it's place.
Solution 4:[4]
Firstly, if you don't want the user to modify the data, then it seems cleaner to simply exclude the field. Including it as a hidden field just adds more data to send over the wire and invites a malicious user to modify it when you don't want them to. If you do have a good reason to include the field but hide it, you can pass a keyword arg to the modelform's constructor. Something like this perhaps:
class MyModelForm(forms.ModelForm):
class Meta:
model = MyModel
def __init__(self, *args, **kwargs):
from django.forms.widgets import HiddenInput
hide_condition = kwargs.pop('hide_condition',None)
super(MyModelForm, self).__init__(*args, **kwargs)
if hide_condition:
self.fields['fieldname'].widget = HiddenInput()
# or alternately: del self.fields['fieldname'] to remove it from the form altogether.
Then in your view:
form = MyModelForm(hide_condition=True)
I prefer this approach to modifying the modelform's internals in the view, but it's a matter of taste.
Solution 5:[5]
For normal form you can do
class MyModelForm(forms.ModelForm):
slug = forms.CharField(widget=forms.HiddenInput())
If you have model form you can do the following
class MyModelForm(forms.ModelForm):
class Meta:
model = TagStatus
fields = ('slug', 'ext')
widgets = {'slug': forms.HiddenInput()}
You can also override __init__
method
class Myform(forms.Form):
def __init__(self, *args, **kwargs):
super(Myform, self).__init__(*args, **kwargs)
self.fields['slug'].widget = forms.HiddenInput()
Solution 6:[6]
If you want the field to always be hidden, use the following:
class MyForm(forms.Form):
hidden_input = forms.CharField(widget=forms.HiddenInput(), initial="value")
If you want the field to be conditionally hidden, you can do the following:
form = MyForm()
if condition:
form.fields["field_name"].widget = forms.HiddenInput()
form.fields["field_name"].initial = "value"
Solution 7:[7]
Example of a model:
models.py
from django.db import models
class YourModel(models.Model):
fieldname = models.CharField(max_length=255, default="default")
In your form, you can add widgets with ModelForm. To make it hidden add 'type': 'hidden'
as shown below?
forms.py
from .models import YourModel
from django import forms
class YourForm(forms.ModelForm):
class Meta:
model = YourModel
fields = ('fieldname',)
widgets = {
'fieldname': forms.TextInput(attrs={'type': 'hidden'}),
}
If you don't know how to add it to your views.py file, here is some videos about it.
If you use Function Based View:
https://www.youtube.com/watch?v=6oOHlcHkX2U
If you use Class Based View:
Solution 8:[8]
{{ form.field}}
{{ form.field.as_hidden }}
with this jinja format we can have both visible form fields and hidden ones too.
Solution 9:[9]
if you want to hide and disable the field to protect the data inside. as others mentioned use the hiddenInput widget and make it disable
in your form init
example:
if not current_user.is_staff:
self.base_fields['pictureValid'].disabled = True
self.base_fields['pictureValid'].widget = forms.HiddenInput()
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | Community |
Solution 3 | SuperBiasedMan |
Solution 4 | |
Solution 5 | |
Solution 6 | |
Solution 7 | |
Solution 8 | Ignatious varghese |
Solution 9 | Amir jodat |