'Connection Failure with PHP and GMail IMAP
I have looked at several tutorials and different explanations but although I have enabled imap in gmai, enabled the permission for insecure activities, my connection string is
imap_open('{imap.gmail.com:993/imap/ssl/novalidate-cert}INBOX', 'email', 'pwd')
and I have not activated the two-factor authentication I still have the same error.
Cannot connect to Gmail: Can not authenticate to IMAP server: [ALERT] Please log in via your web browser
this is all the code
<?php
/* Connecting Gmail server with IMAP */
$connection = imap_open('{imap.gmail.com:993/imap/ssl/novalidate-cert}INBOX', 'email', 'pwd') or die('Cannot connect to Gmail: ' . imap_last_error());
/* Search Emails having the specified keyword in the email subject */
$emailData = imap_search($connection, 'SUBJECT "Article "');
if (! empty($emailData)) {
?>
<table>
<?php
foreach ($emailData as $emailIdent) {
$overview = imap_fetch_overview($connection, $emailIdent, 0);
$message = imap_fetchbody($connection, $emailIdent, '1.1');
$messageExcerpt = substr($message, 0, 150);
$partialMessage = trim(quoted_printable_decode($messageExcerpt));
$date = date("d F, Y", strtotime($overview[0]->date));
?>
<tr>
<td style="width:15%;"><span class="column"><?php echo $overview[0]->from; ?></span></td>
<td class="content-div"><span class="column"><?php echo $overview[0]->subject; ?> - <?php echo $partialMessage; ?></span><span class="date"><?php echo $date; ?></span></td>
</tr>
<?php
} // End foreach
?>
</table>
<?php
} // end if
imap_close($connection);
}
?>
I don't understand why...
Solution 1:[1]
IMAP={imap.gmail.com:993/imap/ssl/novalidate-cert}INBOX
$message = imap_fetchbody($connection, $emailIdent, 1);
https://accounts.google.com/DisplayUnlockCaptcha - go to this url and enable it.
Go to gmail Top right - settings
See all settings - under - quick settings
Forwarding and pop/imap
Enable Imap - save changes
Next go to manage your google account - security
Less secure app access - On
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
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Solution 1 |