'const& , & and && specifiers for member functions in C++
Recently I was reading through the API of boost::optional
and came across the lines:
T const& operator *() const& ;
T& operator *() & ;
T&& operator *() && ;
I also wrote my own program that defines member functions as const&, & and && (Note that I am not speaking about the return type, but the specifiers just before the semi-colons) and they seems to work fine.
I know what it means to declare a member function const, but can anyone explain what it means to declare it const&, & and &&.
Solution 1:[1]
const&
means, that this overload will be used only for const, non-const and lvalue object.
const A a = A();
*a;
&
means, that this overload will be used only for non-const object.
A a;
*a;
&&
means, that this overload will be used only for rvalue object.
*A();
for more information about this feature of C++11 standard you can read this post What is "rvalue reference for *this"?
Solution 2:[2]
It is a member function ref-qualifiers; it is one of the features added in C++11. It is possible to overload non-static member functions based on whether the implicit this
object parameter is an lvalue or an rvalue by specifying a function ref-qualifier (some details).
To specify a ref-qualifier for a non-static member function, you can either qualify the function with &
or &&
.
#include <iostream>
struct myStruct {
void func() & { std::cout << "lvalue\n"; }
void func() &&{ std::cout << "rvalue\n"; }
};
int main(){
myStruct s;
s.func(); // prints "lvalue"
std::move(s).func(); // prints "rvalue"
myStruct().func(); // prints "rvalue"
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Dan Nissenbaum |
Solution 2 |