'Convert dictionary of lists to dictionary of dictionary
Current output is of format, dictionary of lists
{
"majestic-service-1.324.02070909": [
"/home/robotics/arm-services/FeaturesDir.yaml",
"/home/robotics/arm-service/majestic-service.tar.gz"
],
}
and I'm looking to change that output format to something like below.(dictionary of dictionary)
{
"majestic-service-1.324.02070909": {
"yaml_file": "/home/robotics/arm-services/FeaturesDir.yaml",
"tar_file": "/home/robotics/arm-services/majestic-service-1.324.02070909.tar.gz",
"kind": "FeaturesDir"
}
}
Corresponding code snippet that I've tried,
output_dict = {}
for file in application_files:
match = re.match(regex_pattern, os.path.basename(file))
if match:
if os.path.exists(os.path.join(os.path.dirname(file), "FeaturesDir.yaml")):
output_dict[file_without_extension(match.string)] = {os.path.join(os.path.dirname(file), "FeaturesDir.yaml")}
output_dict[file_without_extension(match.string)].append(file)
output_dict["Kind"] = "FeaturesDir"
elif os.path.exists(os.path.join(os.path.dirname(file), "output_path/Deviations.yaml")):
output_dict[file_without_extension(match.string)] = {os.path.join(os.path.dirname(file), "output_path/Deviations")}
output_dict[file_without_extension(match.string)].append(file)
output_dict["Kind"] = "Deviations"
# where the function file_without_extension, will return - majestic-service-1.324.02070909 from majestic-service-1.324.02070909.tar.gz
It reports the following error
AttributeError: 'set' object has no attribute 'append'
What am I doing wrong ?
Solution 1:[1]
The error occurs because in this line output_dict[file_without_extension(match.string)] = {os.path.join(os.path.dirname(file), "output_path/Deviations")}
you're using {} brackets which for python are intended as the data type called set. Sets don't have append attribute, they have add attribute instead but it's a completely different data type. That's why it shows you that kind of error!
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | federicknellus |