'Deserialize using a function of the tag
An API with this internally tagged field structure, with "topic" being the tag:
{
"topic": "Car"
"name": "BMW"
"HP": 250
}
This can be deserialized with
#[derive(Serialize, Deserialize)]
#[serde(tag = "topic")]
pub enum catalog {
CarEntry(Car),
... (other types)
}
#[derive(Serialize, Deserialize)]
pub struct Car {
pub name: String
pub HP: i32
}
It turns out that instead of reporting the topic as just Car
, the API actually sends Car.product1
or Car.product2
etc.
This breaks the deserialization, because the deserializer doesn't know what the type is based on the string. Is there a way to supply a function to chop off the type string so that the correct model is found?
Solution 1:[1]
I don't think serde provides a way to mangle the tag before using it (at least I don't see anything relevant). And the generated serializers for tagged enums are relatively complex, with internal caching if the tag isn't the first field, and whatnot, so I wouldn't want to reproduce that in a custom deserializer.
The cheapest (but not necessarily most efficient) shot at this is to deserialize to serde_json::Value
first, manually process the tag, and then deserialize the serde_json::Value
s to whatever struct you want.
Do that in a custom deserializer, and it starts looking reasonable:
impl<'de> Deserialize<'de> for Catalog {
fn deserialize<D>(d: D) -> Result<Self, <D as Deserializer<'de>>::Error>
where
D: Deserializer<'de>,
{
use serde_json::{Map, Value};
#[derive(Deserialize)]
struct Pre {
topic: String,
#[serde(flatten)]
data: Map<String, Value>,
}
let v = Pre::deserialize(d)?;
// Now you can mangle Pre any way you want to get your final structs.
match v.topic.as_bytes() {
[b'C', b'a', b'r', b'.', _rest @ ..] => Ok(Catalog::CarEntry(
serde_json::from_value(v.data.into()).map_err(de::Error::custom)?,
)),
[b'B', b'a', b'r', b'.', _rest @ ..] => Ok(Catalog::BarEntry(
serde_json::from_value(v.data.into()).map_err(de::Error::custom)?,
)),
_ => return Err(de::Error::unknown_variant(&v.topic, &["Car.…", "Bar.…"])),
}
}
}
Btw, what do you want to do with the suffix of topic
? Throw it away? How do you plan on handling serialization if you do throw it away?
Solution 2:[2]
You can directly use enum
instead of defining extra struct type.
use serde::{Serialize, Deserialize};
#[derive(Serialize, Deserialize, Debug)]
#[serde(tag = "topic")]
pub enum Catalog {
Car { name: String, hp: i32 }
}
fn main() {
let car = Catalog::Car { name: String::from("BMW"), hp: 2000 };
// Convert the Car to a JSON string.
let serialized = serde_json::to_string(&car).unwrap();
// Prints serialized = {"topic":"Car","name":"BMW","hp":2000}
println!("serialized = {}", serialized);
// Convert the JSON string back to a Car.
let deserialized: Catalog = serde_json::from_str(&serialized).unwrap();
// Prints deserialized = Car { name: "BMW", hp: 2000 }
println!("deserialized = {:?}", deserialized);
}
You can use #[serde(rename()]
to rename type in output
use serde::{Serialize, Deserialize};
#[derive(Serialize, Deserialize, Debug)]
#[serde(tag = "topic")]
pub enum Catalog {
#[serde(rename(serialize = "Car", deserialize = "CarEntry"))]
CarEntry(Car),
}
#[derive(Serialize, Deserialize, Debug)]
pub struct Car {
pub name: String,
pub hp: i32
}
fn main() {
let car = Car { name: String::from("BMW"), hp: 2000 };
let catalog = Catalog::CarEntry(car);
// Convert the Car to a JSON string.
let serialized = serde_json::to_string(&catalog).unwrap();
// Prints serialized = {"topic":"Car","name":"BMW","hp":2000}
println!("serialized = {}", serialized);
// Convert the JSON string back to a Car.
let deserialized: Car = serde_json::from_str(&serialized).unwrap();
// Prints deserialized = Car { name: "BMW", hp: 2000 }
println!("deserialized = {:?}", deserialized);
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Caesar |
Solution 2 | Chandan |