'Displaying child records based on parent id from URL
I have one model Dataset
and another one called DatasetReview
, where DatasetReview
has a foreign key connection to Dataset
. I would like to display all of the DatasetReview
models that are tied to a specific Dataset
in a separate page.
I can currently view each Dataset
like so: http://127.0.0.1:8000/dataset/3/
and would like to see all of the DatasetReview
models for Dataset
3 like so: http://127.0.0.1:8000/dataset/3/reviews
But I am unsure how to set this up.
I am not sure how to phrase this question well so I had difficulty finding other posts discussing how to do something like this. Here is my code:
urls.py
:
from django.urls import path
from .views import (
DatasetListView,
DatasetDetailView,
DatasetCreateView,
DatasetUpdateView,
DatasetDeleteView,
DatasetReviewsView
)
from . import views
urlpatterns = [
path('', DatasetListView.as_view(), name='argo-home'),
path('dataset/<int:pk>/', DatasetDetailView.as_view(), name='dataset-detail'),
path('dataset/new/', DatasetCreateView.as_view(), name='dataset-create'),
path('dataset/<int:pk>/update', DatasetUpdateView.as_view(), name='dataset-update'),
path('dataset/<int:pk>/delete', DatasetDeleteView.as_view(), name='dataset-delete'),
path('dataset/<int:pk>/reviews', DatasetReviewsView.as_view(), name='dataset-review'),
path('about/', views.about, name='argo-about'),
]
views.py
:
from django.shortcuts import render
from django.contrib.auth.mixins import LoginRequiredMixin, UserPassesTestMixin
from django.views.generic import (
ListView,
DetailView,
CreateView,
UpdateView,
DeleteView
)
from .models import Dataset, DatasetReview
def home(request):
context = {
'datasets' : Dataset.objects.all(),
}
return render(request, 'argo/home.html', context)
class DatasetListView(ListView):
model = Dataset
template_name = 'argo/home.html' # <app>/<model>_<viewtype>.html
context_object_name = 'datasets'
ordering = ['-date_posted']
class DatasetDetailView(DetailView):
model = Dataset
class DatasetCreateView(LoginRequiredMixin, CreateView):
model = Dataset
fields = ['title', 'description', 'access']
def form_valid(self, form):
form.instance.author = self.request.user
form.instance.affiliation = self.request.user.affiliation
return super().form_valid(form)
class DatasetUpdateView(LoginRequiredMixin, UserPassesTestMixin, UpdateView):
model = Dataset
fields = ['title', 'description']
def form_valid(self, form):
form.instance.author = self.request.user
return super().form_valid(form)
def test_func(self):
Dataset = self.get_object()
if self.request.user == Dataset.author:
return True
return False
class DatasetDeleteView(LoginRequiredMixin, UserPassesTestMixin, DeleteView):
model = Dataset
success_url = '/'
def test_func(self):
dataset = self.get_object()
if self.request.user == dataset.author:
return True
return False
class DatasetReviewsView(DetailView):
model = DatasetReview
success_url = '/'
def test_func(self):
datasetReview = self.get_object()
if self.request.user == datasetReview.author:
return True
return False
def about(request):
return render(request, 'argo/about.html', {'title': 'About'})
models.py
:
from django.db import models
from django.utils import timezone
from django.core.validators import MaxValueValidator, MinValueValidator
from django.urls import reverse
from users.models import User, Affiliation
# from django.contrib.auth.models import User
class Dataset(models.Model):
title = models.CharField(max_length=100)
description = models.TextField()
date_posted = models.DateTimeField(default=timezone.now)
affiliation = models.ForeignKey(Affiliation, on_delete=models.CASCADE, related_name='posted_datasets')
access = models.ManyToManyField(Affiliation, related_name='available_datasets')
author = models.ForeignKey(User, on_delete=models.CASCADE)
def __str__(self):
return self.title
def get_absolute_url(self):
return reverse('dataset-detail', kwargs={'pk' : self.pk})
class DatasetReview(models.Model):
dataset = models.ForeignKey(Dataset, on_delete=models.CASCADE, related_name='reviews_obj')
reviewer = models.ForeignKey(User, on_delete=models.CASCADE, related_name='reviews')
comments = models.TextField()
rating = models.FloatField(
default=3.0,
validators=[MaxValueValidator(5.0), MinValueValidator(1.0)]
)
def __str__(self):
return self.dataset.title + ' review by ' + self.reviewer.username
def get_absolute_url(self):
return reverse('dataset-review', kwargs={'rpk' : self.pk})
admin.py
:
from django.contrib import admin
from .models import Dataset, DatasetReview
admin.site.register(Dataset)
admin.site.register(DatasetReview)
Any tips would be super helpful, very new to django.
Solution 1:[1]
Figured this out.
The key is within class DatasetReviewsView(DetailView)
in views.py
. I first needed to change this inheritance to a ListView
to enable what I was looking for.
Next, I just needed to provide context for what I wanted to show in my html page. This is easily done by overriding the get_context_data
function, which provides the context data for templates displaying this class based view.
It makes it very easy to leverage python to provide the information I want. I could query the id of the dataset I was looking at with id = self.kwargs['pk']
(which must be included in the function parameters for get_context_data
), and then I could just filter all reviews to just those with a dataset matching this id. Within the html I could then iterate over the variable num_reviews
.
There is some other code that averages all the ratings to provide an overall rating as well.
class DatasetReviewsView(ListView):
model = DatasetReview
context_object_name = 'reviews'
success_url = '/'
def get_context_data(self, **kwargs):
id = self.kwargs['pk']
context = super(DatasetReviewsView, self).get_context_data(**kwargs)
context['id'] = id
context['name'] = Dataset.objects.get(pk=id).title
context['num_reviews'] = len(DatasetReview.objects.filter(dataset=id))
tot = 0
for review in DatasetReview.objects.filter(dataset=id):
tot += review.rating
context['avg_rating'] = tot / context['num_reviews']
return context
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | donallw |