'filter object becomes empty after iteration? [duplicate]
I'm learning how to use the filter
function.
This is the code I've written:
people = [{'name': 'Mary', 'height': 160},
{'name': 'Isla', 'height': 80},
{'name': 'Sam'}]
people2 = filter(lambda x: "height" in x, people)
As you can see what I'm trying to do is to remove all the dictionaries that don't contain the 'height'
key.
The code works properly, in fact if I do:
print(list(people2))
I get:
[{'name': 'Mary', 'height': 160}, {'name': 'Isla', 'height': 80}]
The problem is that if I do it twice:
print(list(people2))
print(list(people2))
the second time, I get an empty list.
Can you explain me why?
Solution 1:[1]
It's because what filter really turns is an iterator. This iterator doesn't really do anything until you start to use it's results, in this case when you cast it to a list. people2
is this thing that's ready to filter the list of people, then when list is called on it, it iterates through the list of people and delivers the filtered result. Now that iterator is done, there's nothing left for it to iterate over, so when you call list on it a second time, there's nothing there.
Read this for some more details - Lazy evaluation python
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | OldGeeksGuide |