'Haskell Monoid Instance Question for a newtype
I am trying to define an instance:
newtype Join a = Join { getJoin :: a -> Bool }
deriving Generic
instance Monoid (Join a) where
f <> g = ???
mempty = ???
The goal is that the function foldMap Join should return True if all functions in the list are true, and false if all are not true.
I understand foldMap, and the instances of Sum and Product for Monoid but am otherwise quite new to writting newtype instances of Monoid. Any help in the right direction would be appreciated. Thank you.
Solution 1:[1]
You can make an new function that returns True
if both the first and second function return True
, by using (&&)
. Then the mempty
is a Join
function that is True
for all input:
instance Monoid (Join a) where
Join f <> Join g = Join (\x -> f x && g x)
mempty = Join (const True)
Since the introduction of the Semigroup
, the (<>)
function is an instance of the Semigroup
however:
import Control.Applicative(liftA2)
instance Semigroup (Join a) where
Join f <> Join g = Join (liftA2 (&&) f g)
instance Monoid (Join a) where
mappend = (<>)
mconcat js = Join (\x -> all (($ x) . getJoin) js)
mempty = Join (const True)
Solution 2:[2]
Your type Join a
is isomorphic to a -> All
, which already has the Monoid
instance that you want. As such, you can get the instance on your type without having to implement anything yourself, like this:
{-# LANGUAGE DerivingVia #-}
import Data.Monoid
newtype Join a = Join { getJoin :: a -> Bool }
deriving Generic -- not needed for the Monoid instance; I only left it here to show you how to do two different kinds of deriving on the same type, since you derived this already in your question
deriving (Semigroup, Monoid) via a -> All
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Willem Van Onsem |
Solution 2 | Iceland_jack |