'How can I add text labels to a Plotly scatter plot in Python?
I'm trying to add text labels next to the data points in a Plotly scatter plot in Python but I get an error.
How can I do that?
Here is my dataframe:
world_rank university_name country teaching international research citations income total_score num_students student_staff_ratio international_students female_male_ratio year
0 1 Harvard University United States of America 99.7 72.4 98.7 98.8 34.5 96.1 20,152 8.9 25% NaN 2011
Here is my code snippet:
citation = go.Scatter(
x = "World Rank" + timesData_df_top_50["world_rank"], <--- error
y = "Citation" + timesData_df_top_50["citations"], <--- error
mode = "lines+markers",
name = "citations",
marker = dict(color = 'rgba(48, 217, 189, 1)'),
text= timesData_df_top_50["university_name"])
The error is shown below.
TypeError: ufunc 'add' did not contain a loop with signature matching types dtype('<U32') dtype('<U32') dtype('<U32')
Solution 1:[1]
You can include the text labels in the text
attribute. To make sure that they are displayed on the scatter plot, set mode='lines+markers+text'
. See the Plotly documentation on text and annotations. I included an example below based on your code.
import plotly.graph_objects as go
import pandas as pd
df = pd.DataFrame({'world_rank': [1, 2, 3, 4, 5],
'university_name': ['Harvard', 'MIT', 'Stanford', 'Cambridge', 'Oxford'],
'citations': [98.8, 98.7, 97.6, 97.5, 96]})
layout = dict(plot_bgcolor='white',
margin=dict(t=20, l=20, r=20, b=20),
xaxis=dict(title='World Rank',
range=[0.9, 5.5],
linecolor='#d9d9d9',
showgrid=False,
mirror=True),
yaxis=dict(title='Citations',
range=[95.5, 99.5],
linecolor='#d9d9d9',
showgrid=False,
mirror=True))
data = go.Scatter(x=df['world_rank'],
y=df['citations'],
text=df['university_name'],
textposition='top right',
textfont=dict(color='#E58606'),
mode='lines+markers+text',
marker=dict(color='#5D69B1', size=8),
line=dict(color='#52BCA3', width=1, dash='dash'),
name='citations')
fig = go.Figure(data=data, layout=layout)
fig.show()
Sources
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Source: Stack Overflow
Solution | Source |
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Solution 1 |