'How to access the class itself from within a class without using its name [duplicate]
Is it possible to access the class
itself inside of a classes function:
class MyClass {
static get myFunction() { return "foo"; }
constructor() {
console.log(MyClass.myFunction); // "foo" -- it works when using its name. This is what we want but without using the name
console.log(this.myFunction); //undefined
console.log(this.prototype.myFunction); //Cannot read property 'myFunction' of undefined
}
}
new MyClass();
Is it possible to achieve the same as you do with MyClass.myFunction()
and access the static
methods without using the name of the class (in this case without using MyClass
in this example?
Something like this.master.myFunction()
(I’m just making master
up here it’s obviously not called master)
JSBin: https://jsbin.com/hawituxosu/1/edit?js,console
Is that even possible? Thank you!
Solution 1:[1]
you can use constructor
for this
Returns a reference to the Object constructor function that created the instance object
The constructor property has three purposes:
1. Get the class object.
2. Create an new instance
3. Invoke super constructor
class MyClass {
static get myFunction() { return "foo"; }
constructor() {
console.log(this.constructor.myFunction);
}
}
new MyClass();
Solution 2:[2]
an option you can do here is to call static method inside an instance method and call that instance method
class MyClass {
static get myFunction() { return "foo"; }
constructor() {
console.log(MyClass.myFunction); // "foo" -- whith using its name it works. This is what we want but without using the name
console.log(this.constructor.myFunction);
}
myFunction2() {
return this.constructor.myFunction();
}
}
const master = new MyClass();
master.myFunction2();
Solution 3:[3]
this.constructor.myFoo
The constructor property helps you here
Solution 4:[4]
You could work around getting to the class name using:
this.__proto__.constructor.name // MyClass
class MyClass {
static get myFunction() { return "foo"; }
constructor() {
console.log(eval(this.__proto__.constructor.name + ".myFunction")); //foo
}
}
new MyClass();
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | Artyom Amiryan |
Solution 3 | |
Solution 4 | Ahmad |