'How to convert curl -F command into python code with requests?

I am developing with apis however I faced with a problem that I have never met.

curl -F "media=@IMAGE_NAME" 'xxxx url'

How do I convert it into python code with requests?

python python-requests

Solution 1:^[1]

I solved this problem.

files = { 'media': open(image_name, 'rb') }

Then

requests.post(url, files=files)

see http://www.python-requests.org/en/latest/user/quickstart/#post-a-multipart-encoded-file

Solution 2:^[2]

There's a great example of a POST request in the manual. I think yours specifically would be:

r = requests.post("xxx url", data={"media": "@IMAGE_NAME"})

Solution 3:^[3]

As per your case :

def command_string_generator(method, token, port, account,container=None, obj=None, headers_in=None, curlhead=None):
    url = 'xxxx url'
    image = "media=@IMAGE_NAME"
    command_string = 'curl -F %s %s ' % (image ,url)
    print command_string
    return command_string

you can use a function like this as per your needs with -F and change accordingly. Hope this might be helpful.Additional parameters are just for convienience.

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'How to convert curl -F command into python code with requests?

Solution 1:[1]

Solution 2:[2]

Solution 3:[3]

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