'How to deal with 401 (unauthorised) in python requests
What I want to do is GET from a site and if that request returns a 401, then redo my authentication wiggle (which may be out of date) and try again. But I don't want to try a third time, since that would be my authentication wiggle having the wrong credentials. Does anyone have a nice way of doing this that doesn't involve properly ugly code, ideally in python requests library, but I don't mind changing.
Solution 1:[1]
It doesn't get any less ugly than this, I think:
import requests
from requests.auth import HTTPBasicAuth
response = requests.get('http://your_url')
if response.status_code == 401:
response = requests.get('http://your_url', auth=HTTPBasicAuth('user', 'pass'))
if response.status_code != 200:
# Definitely something's wrong
Solution 2:[2]
You could have wrapped this in a function and used a decorator to evaluate the response and retry the auth on 401. Then you only need to decorate any function that requires this re-auth logic....
Update:
As requested, a code example. I'm afraid this one is an old piece of code, Python 2 based, but you'll get the idea. This one will retry an http call a number of times as defined in settings.NUM_PLATFORM_RETRIES
and will call a refresh_token
on auth failures. you can adjust the use case and result to whatever.
You can then use this decorator around methods:
@retry_on_read_error
def some_func():
do_something()
def retry_on_read_error(fn):
"""
Retry Feed reads on failures
If a token refresh is required it is performed before retry.
This decorator relies on the model to have a refresh_token method defined, othewise it will fail
"""
@wraps(fn)
def _wrapper(self, *args, **kwargs):
for i in range(settings.NUM_PLATFORM_RETRIES):
try:
res = fn(self, *args, **kwargs)
try:
_res = json.loads(res)
except ValueError:
# not a json response (could be local file read or non json data)
return res
if 'error' in _res and _res['error']['status'] in (401, 400):
raise AccessRefusedException(_res['error']['message'])
return res
except (urllib2.URLError, IOError, AccessRefusedException) as e:
if isinstance(e, AccessRefusedException):
self.refresh_token()
continue
raise ApiRequestFailed(
"Api failing, after %s retries: %s" % (settings.NUM_PLATFORM_RETRIES, e), args, kwargs
)
return _wrapper
Solution 3:[3]
You can use something like this
# 401 retry strategy
import requests
from requests import Request, Session, RequestException
class PreparedRequest:
"""
Class to make Http request with 401 retry
"""
failedRequests = []
defaultBaseUrl = "https://jsonplaceholder.typicode.com"
MAX_RETRY_COUNT = 0
def __init__(self, method, endpoint,
baseurl=defaultBaseUrl, headers=None, data=None, params=None):
"""
Constructor for PreparedRequest class
@param method: Http Request Method
@param endpoint: endpoint of the request
@param headers: headers of the request
@param data: data of request
@param params: params of the request
"""
self.method = method
self.url = baseurl + endpoint
self.headers = headers
self.data = data
self.params = params
self.response = None
def send(self):
"""
To send http request to the server
@return: response of the request
"""
req = Request(method=self.method, url=self.url, data=self.data,
headers=self.headers,params=self.params)
session = Session()
prepared = session.prepare_request(req)
response = session.send(prepared)
if response.status_code == 200:
PreparedRequest.failedRequests.append(self)
PreparedRequest.refresh_token()
elif response.status_code == 502:
raise Exception(response.raise_for_status())
else:
self.response = session.send(prepared)
@staticmethod
def refresh_token():
if PreparedRequest.MAX_RETRY_COUNT > 3:
return
print("Refreshing the token")
# Write your refresh token strategy here
PreparedRequest.MAX_RETRY_COUNT += 1
total_failed = len(PreparedRequest.failedRequests)
for i in range(total_failed):
item = PreparedRequest.failedRequests.pop()
item.send()
r = PreparedRequest(method="GET", endpoint="/todos/")
r.send()
print(r.response.json())
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | José Tomás Tocino |
Solution 2 | |
Solution 3 | Amir Saleem |