'How to extract .zst files into a pandas dataframe
I'm a bit of a beginner when it comes to Python, but one of my projects from school needs me to perform classification algorithms on this reddit popularity dataset. The files are huge .zst files and can be found here: https://files.pushshift.io/reddit/submissions/ Anyway, I'm just not sure how to extract this onto a database, as the assignments we've had so far just used .csv datasets which I could easily put into a pandas dataframe. I stumbled upon a different post and I tried using the code:
def transform_zst_file(self,infile):
zst_num_bytes = 2**22
lines_read = 0
dctx = zstd.ZstdDecompressor()
with dctx.stream_reader(infile) as reader:
previous_line = ""
while True:
chunk = reader.read(zst_num_bytes)
if not chunk:
break
string_data = chunk.decode('utf-8')
lines = string_data.split("\n")
for i, line in enumerate(lines[:-1]):
if i == 0:
line = previous_line + line
self.appendData(line, self.type)
lines_read += 1
if self.max_lines_to_read and lines_read >= self.max_lines_to_read:
return
previous_line = lines[-1]
But I am not entirely sure how to put this into a pandas dataframe, or put only a certain percentage of datapoints into the dataframe if the file is too big. Any help would be very appreciated!
The following code only crashes my computer every time i try to run it:
import zstandard as zstd
your_filename = "..."
with open(your_filename, "rb") as f:
data = f.read()
dctx = zstd.ZstdDecompressor()
decompressed = dctx.decompress(data)
Might be due to the size of the file being too big, is there anyway to extract just a percentage of this file into the pandas dataframe?
Solution 1:[1]
The file has been compressed using Zstandard (https://github.com/facebook/zstd), a compression library.
The easiest thing to do for you will probably be to install python-zstandard (https://pypi.org/project/zstandard/) using
pip install zstandard
and then in a python script run something like
import zstandard as zstd
your_filename = "..."
with open(your_filename, "rb") as f:
data = f.read()
dctx = zstd.ZstdDecompressor()
decompressed = dctx.decompress(data)
Now you can either use the decompressed data directly or write it to some file and then load it to pandas. Good luck!
Solution 2:[2]
I used the TextIOWrapper from io module.
with open(file_name, 'rb') as fh:
dctx = zstandard.ZstdDecompressor(max_window_size=2147483648)
stream_reader = dctx.stream_reader(fh)
text_stream = io.TextIOWrapper(stream_reader, encoding='utf-8')
for line in text_stream:
obj = json.loads(line)
# HANDLE OBJECT LOGIC HERE
Solution 3:[3]
I stumbled across a similar Reddit Dataset consisting of zst
dumps.
In order to iterate over the content of your zst file, I used the following code which you could run as a script:
import zstandard
import os
import json
import sys
from datetime import datetime
import logging.handlers
log = logging.getLogger("bot")
log.setLevel(logging.DEBUG)
log.addHandler(logging.StreamHandler())
def read_lines_zst(file_name):
with open(file_name, 'rb') as file_handle:
buffer = ''
reader = zstandard.ZstdDecompressor(max_window_size=2**31).stream_reader(file_handle)
while True:
chunk = reader.read(2**27).decode()
if not chunk:
break
lines = (buffer + chunk).split("\n")
for line in lines[:-1]:
yield line, file_handle.tell()
buffer = lines[-1]
reader.close()
if __name__ == "__main__":
file_path = sys.argv[1]
file_size = os.stat(file_path).st_size
file_lines = 0
file_bytes_processed = 0
created = None
field = "subreddit"
value = "wallstreetbets"
bad_lines = 0
try:
for line, file_bytes_processed in read_lines_zst(file_path):
try:
obj = json.loads(line)
created = datetime.utcfromtimestamp(int(obj['created_utc']))
temp = obj[field] == value
except (KeyError, json.JSONDecodeError) as err:
bad_lines += 1
file_lines += 1
if file_lines % 100000 == 0:
log.info(f"{created.strftime('%Y-%m-%d %H:%M:%S')} : {file_lines:,} : {bad_lines:,} : {(file_bytes_processed / file_size) * 100:.0f}%")
except Exception as err:
log.info(err)
log.info(f"Complete : {file_lines:,} : {bad_lines:,}")
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Bimba Shrestha |
Solution 2 | Shahnawaz Akhtar |
Solution 3 | aryashah2k |