'How to redirect to dynamic URL inside FastAPI endpoint
I'm doing a feature where the user on their profile page makes changes (not related to the user model). Everything is implemented through static HTML
templates. I need the user to click on the button and return to the same page (their profile page) after processing the request.
html
<td><a href="{{ url_for('decline_event_invite', pk=invite.id) }}" class="btn blue lighten-2">Accept</a></td>
endpoints.py
@router.get('/invite/{pk}/decline')
async def decline_event_invite(
request: Request,
pk: int,
user_id: str = Depends(get_current_user),
service: InviteService = Depends(),
):
await service.invite_decline(pk)
...
--> here I want redirect to user profile page
return RedirectResponse('DYNAMIC URL WITH ARGS')
profile.py
@router.get('/{pk}')
async def user_profile(
request: Request,
pk: int,
service: UserService = Depends()
):
user = await service.get_user_info(pk)
events_invites = await service.get_user_events_invite_list(pk)
return templates.TemplateResponse(
'profile.html',
context=
{
'request': request,
'user': user,
'events_invites': events_invites,
}
)
But I can't find anywhere how to do a redirect similar to the logic that applies to templates. For example:
<a href="{{ url_for('user_profile', pk=pk) }}">Sender</a>
Solution 1:[1]
You can use url_for() function and pass the (**kwargs) path parameters.
import uvicorn
from fastapi import FastAPI, Request
from fastapi.templating import Jinja2Templates
from fastapi.responses import RedirectResponse
import urllib
from fastapi import APIRouter
router = APIRouter()
templates = Jinja2Templates(directory="templates")
@router.get('/invite/{pk}/decline')
async def decline_event_invite(request: Request, pk: int):
redirect_url = request.url_for('user_profile', **{ 'pk' : pk})
return RedirectResponse(redirect_url)
@router.get('/{pk}')
async def user_profile(request: Request, pk: int):
return templates.TemplateResponse("profile.html", {"request": request, "pk": pk})
if __name__ == "__main__":
uvicorn.run(router, host='127.0.0.1', port=8000, debug=True)
In case you need to pass query params as well, use the following sample code (make sure to import urllib):
parsed = list(urllib.parse.urlparse(redirect_url))
parsed[4] = urllib.parse.urlencode({**{ 'username' : "name"}})
new_redirect_url = urllib.parse.urlunparse(parsed)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
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Solution 1 |