'Insert And Retrieve Data in MySQL with $.post Noob Question
Trying to insert data into MySQL database with PHP. I don't want to refresh the page. The data isn't inserted when I press the Send Message button, but the data is displayed. Please help a noob out. Here's the HTML:
<!DOCTYPE html>
<html lang="en-US">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>HTML Contact Form</title>
<script src="https://code.jquery.com/jquery-3.6.0.min.js" integrity="sha256-/xUj+3OJU5yExlq6GSYGSHk7tPXikynS7ogEvDej/m4=" crossorigin="anonymous"></script>
<link rel="stylesheet" href="style.css" type="text/css">
</head>
<body>
<div class="form">
<form method="POST" action="form.php" id="foo" name="foo">
<h1>Contact Form</h1>
<table>
<tr>
<td>
<label for="fname">Full Name:</label><br>
<input type="text" name="fname" placeholder="John Doe" id="">
</td>
</tr>
<tr>
<td>
<label for="email">Your Email:</label><br>
<input type="email" name="email" placeholder="[email protected]" id="">
</td>
</tr>
<tr>
<td>
<label for="msg">Your Message:</label><br>
<textarea name="msg" placeholder="Type your message..." id="" cols="30" rows="10"></textarea>
</td>
</tr>
<tr>
<td>
<input type="submit" name="submit" value="Send Message">
</td>
</tr>
</table>
</form>
</div>
<p id="target">
</p>
<script>
$(function() {
$("#foo").submit(function(event){
// Stop form from submitting normally
event.preventDefault();
/* Serialize the submitted form control values to be sent to the web server with the request */
var formValues = $(this).serialize();
// Send the form data using post
$.post("form.php", formValues, function(response){
$('#target').load('show.php');
});
});
});
</script>
</body>
</html>
Here's form.php which is supposed to insert data into the database:
<?php
error_reporting(E_ALL);
log_errors(1);
display_errors(1);
if(isset($_POST['submit']))
{
$name = $_POST['fname'];
$email = $_POST['email'];
$message = $_POST['msg'];
//database details. You have created these details in the third step. Use your own.
$host = "localhost";
$username = "user";
$password = "GoTn_1290";
$dbname = "form_entriesdb";
//create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$con = mysqli_connect($host, $username, $password, $dbname);
//check connection if it is working or not
if (!$con)
{
die("Connection failed!" . mysqli_connect_error());
}
//This below line is a code to Send form entries to database
$sql = $con->prepare("INSERT INTO contactform_entries (name_fld, email_fld, msg_fld) VALUES (?, ?, ?)");
$sql->bind_param("sss", $name, $email, $message);
$sql->execute();
//connection closed.
$sql->close();
$con->close();
}
?>
And here's what displays my data, show.php:
<?php
$servername = "localhost";
$username = "user";
$password = "secret";
$dbname = "form_entriesdb";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql2 = "SELECT id, name_fld, email_fld, msg_fld FROM contactform_entries";
$result = $conn->query($sql2);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["id"]. " - Name: " . $row["name_fld"]. " " . $row["email_fld"]. " " . $row["msg_fld"] . "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
Solution 1:[1]
I ended up using .ajax instead of .post. I also changed my filename to index.php. I can't find the website where I got my code from, but here it is:
<!DOCTYPE html>
<html>
<head>
<title>Insert data in MySQL database using Ajax</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
</head>
<body>
<div style="margin: auto;width: 60%;">
<div class="alert alert-success alert-dismissible" id="success" style="display:none;">
<a href="#" class="close" data-dismiss="alert" aria-label="close">×</a>
</div>
<form id="fupForm" name="form1" method="post">
<div class="form-group">
<label for="email">Name:</label>
<input type="text" class="form-control" id="name" placeholder="Name" name="name">
</div>
<div class="form-group">
<label for="pwd">Email:</label>
<input type="email" class="form-control" id="email" placeholder="Email" name="email">
</div>
<div class="form-group">
<label for="pwd">Phone:</label>
<input type="text" class="form-control" id="phone" placeholder="Phone" name="phone">
</div>
<div class="form-group" >
<label for="pwd">City:</label>
<select name="city" id="city" class="form-control">
<option value="">Select</option>
<option value="Delhi">Delhi</option>
<option value="Mumbai">Mumbai</option>
<option value="Pune">Pune</option>
</select>
</div>
<input type="button" name="save" class="btn btn-primary" value="Save to database" id="butsave">
</form>
</div>
<p id="target">
</p>
<script>
$(document).ready(function() {
$('#butsave').on('click', function() {
var name = $('#name').val();
var email = $('#email').val();
var phone = $('#phone').val();
var city = $('#city').val();
if(name!="" && email!="" && phone!="" && city!=""){
$.ajax({
url: "save.php",
type: "POST",
data: {
name: name,
email: email,
phone: phone,
city: city
},
cache: false,
success: function(dataResult){
var dataResult = JSON.parse(dataResult);
if(dataResult.statusCode==200){
$("#butsave").removeAttr("disabled");
$('#fupForm').find('input:text').val('');
$("#success").show();
$('#success').html('Data added successfully !');
$('#target').load('show.php');
}
else if(dataResult.statusCode==201){
alert("Error occured !");
}
}
});
}
else{
alert('Please fill all the fields !');
}
});
});
</script>
</body>
</html>
Here's save.php. It's the code that inserts data into the database:
<?php
include 'database.php';
$name=$_POST['name'];
$email=$_POST['email'];
$phone=$_POST['phone'];
$city=$_POST['city'];
$sql = $con->prepare("INSERT INTO `crud`( `name`, `email`, `phone`, `city`) VALUES (?,?,?,?)");
$sql->bind_param("ssss", $name, $email, $phone, $city);
$rc = $sql->execute();
if (true===$rc) {
echo json_encode(array("statusCode"=>200));
}
else {
echo json_encode(array("statusCode"=>201));
}
//connection closed.
$sql->close();
$con->close();
?>
Here is show.php:
<?php
include 'database.php';
// Check connection
if ($con->connect_error) {
die("Connection failed: " . $con->connect_error);
}
$query = "SELECT name, email, phone, city FROM crud";
$result = $con->query($query);
if ($result->num_rows > 0) {
// output data of each row
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
echo $row["name"]. " " . $row["email"]. " " . $row["phone"]. " " . $row["city"]."<br>";
}
} else {
echo "0 results";
}
$result -> free_result();
$con->close();
?>
And here are the database connection details, database.php:
<?php
$servername = "localhost";
$username = "user";
$password = "secret";
$db="school";
$con = mysqli_connect($servername, $username, $password,$db);
?>
The code posted is entirely functional.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Neo |