'Java Execution timeout

I'm trying to solve BaekJoon 12865 problem by Java.
But it evaluates Execution timeout.
There isn't any error in eclipse compiler.
Someone know about problem in my codes.
Please tell me what did i do wrong.
This problem is find Maximum value in K weight by N objects that has V(value) and W(weight).

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class Main {

public static void main(String[] args) {
    class Object implements Comparable<Object>{
        private int W;   //object's weight
        private int V;   //object's value
        private int VbyW;
        public Object(int w, int v) {
            this.W = w;
            this.V = v;
            this.VbyW = v/w;  // value by weight
        }
        @Override
        public int compareTo(Object object)
        {
            if (object.VbyW > VbyW)
            {
                return 1;
            }else if(object.VbyW < VbyW){
                return -1;
            }else
                return 0;               
        }
    }
    int N;   // number of object
    int K;   // Maximum of weight that I can have
    Scanner sc = new Scanner(System.in);
    N = sc.nextInt();
    K = sc.nextInt(); 

    //first I got number of objects and Maximum weight

    int W[] = new int[N];
    int V[] = new int[N];
    Object[] obj = new Object[N];
    ArrayList<Object> objs = new ArrayList<>(); 
    for (int i=0;i<N;i++)
    {
        W[i] = sc.nextInt();
        V[i] = sc.nextInt();
        obj[i] = new Object(W[i],V[i]);     
        objs.add(obj[i]);
    } // I'll get all object's value and weight
    
    Collections.sort(objs, Collections.reverseOrder());
    int totalV=0;   
    for(int j=0;j<N;j++)
    {
        while(K>objs.get(j).W)
        {
            totalV +=objs.get(j).V;
        }
    } // I'll find Maximum value in K weight by objects
    System.out.println(totalV);
    sc.close();
}

}

problem site : https://www.acmicpc.net/problem/12865



Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source