Keeping punctuation in string while getting dictionary values

Question

I have the below code and looking to get abc, cde as output. I have tried to convert the Nones to empty strings using str(i or ' ') for i in m and got abc cde as output. Is it possible to isolate the comma , such that the output would be abc, cde?

d = {'1':'a', '2':'b', '3':'c', '4':'d', '5':'e'}
s = '123, 345'
m = [d.get(i) for i in s]
print(''.join(map(str, m)))

# output -> abcNoneNonecde

I managed to get the desired output by adding ',':',' to the dictionary, like below. But wondering if there's another way of achieving the same?

d = {'1':'a', '2':'b', '3':'c', '4':'d', '5':'e'}
d[','] = ','
s = '123, 345'
m = [d.get(i) for i in s]
output = [str(i or ' ') for i in m]
print(''.join(map(str, output)))

# output -> abc, cde

Answer 1

Use i as the default value for get.

d = {'1':'a', '2':'b', '3':'c', '4':'d', '5':'e'}
s = '123, 345'
m = [d.get(i, i) for i in s]
print(''.join(map(str, m)))

Or all in one line.

print(''.join(d.get(i, i) for i in s))

We can drop the mapping to str because all values are already a string.

Answer 2

Use the maketrans and translate functions

txt = "123, 345"

x = "12345"
y = "abcde"

mytable = txt.maketrans(x, y)

print(txt.translate(mytable))

This is the w3school link that explain the function: https://www.w3schools.com/python/ref_string_translate.asp