'Libre office configuration file bootstrap.ini corrupt
I am using the libreoffice-convert package to convert a Word file into PDF. But when I try to convert I get this error. How do I fix this? I have installed LibreOffice 7.0.5
Console log is showing this error:
'C:\\Program Files\\LibreOffice\\program\\soffice.exe -env:UserInstallation=file://C:\\Users\\thesa\\AppData\\Local\\Temp\\soffice-10416-bQefydwUfs2F --headless --convert-to .pdf --outdir C:\\Users\\thesa\\AppData\\Local\\Temp\\libreofficeConvert_-10416-v46bO7ljGHRe C:\\Users\\thesa\\AppData\\Local\\Temp\\libreofficeConvert_-10416-v46bO7ljGHRe\\source'
							
						Solution 1:[1]
Try this, you will probably need administrator rights.
- Locate and copy your orignal file, for example to "bootstrap.ini.org", in the same directory1.
 - Open the file and replace its contents with this, which is a copy of my file:
[Bootstrap] InstallMode=<installmode> ProductKey=LibreOffice 7.0 UserInstallation=$SYSUSERCONFIG/LibreOffice/4 
Another option is to re-install or repair the installation.
Note 1: This copy is just in case you need to revert.
Solution 2:[2]
//let data = await fs.promises.readFile(path_to_excel_file);
            let data = fs.readFileSync(path_to_excel_file)
            let pdfFile = await libreConvert(data, '.pdf', undefined);
            await fs.promises.writeFile(`${__dirname}/${docName}.pdf`, pdfFile);
            res.download(`${__dirname}/${docName}.pdf`)
It will works File. Even If don't work then follow below step: Add this line 14 after instalDir
const installDir = tmp.dirSync({prefix: 'soffice', unsafeCleanup: true, ...tmpOptions});
const posixInstallDir = installDir.name.split(path.sep).join(path.posix.sep);
then Replace commant
let command = `${results.soffice}  --headless --convert-to ${format}`;
That's it..
Solution 3:[3]
-env:UserInstallation needs to be in URI form.
Note: also that you using file:// this should be file:/// see File URI scheme
-env:UserInstallation=file:///C:/Users/thesa/AppData/Local/Temp/soffice-10416-bQefydwUfs2F
>>> from pathlib import Path
>>> def get_posix(mypath) -> str:
>>>     p = Path(mypath)
>>>     return p.as_posix()
>>> tmp = "C:\\Users\\thesa\\AppData\\Local\\Temp\\soffice-10416-bQefydwUfs2F"
>>> get_posix(tmp)
'C:/Users/thesa/AppData/Local/Temp/soffice-10416-bQefydwUfs2F'
or
>>> from pathlib import Path
>>> tmp = Path("C:\\Users\\thesa\\AppData\\Local\\Temp\\soffice-10416-bQefydwUfs2F")
>>> tmp.as_uri()
'file:///C:/Users/thesa/AppData/Local/Temp/soffice-10416-bQefydwUfs2F'
    					Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source | 
|---|---|
| Solution 1 | the busybee | 
| Solution 2 | Prabhu S | 
| Solution 3 | Amour Spirit | 

