Passing dataframe and using its name to create the csv file

Question

I have a requirment where i need to pass different dataframes and print the rows in dataframes to the csv file and the name of the file needs to be the dataframe name. Example Below is the data frame

 **Dataframe**

  | Students | Mark | Grade |
  | -------- | -----|------ |
  | A        | 90   | a     |
  | B        | 60   | d     |
  | C        | 40   | b     |
  | D        | 45   | b     |
  | E        | 66   | d     |
  | F        | 80   | b     |
  | G        | 70   | c     |   

A_Grade=df.loc[df['grade']=='a']

B_Grade=df.loc[df['grade']=='b']

C_Grade=df.loc[df['grade']=='c']

D_Grade=df.loc[df['grade']=='d']

E_Grade=df.loc[df['grade']=='e']

F_Grade=df.loc[df['grade']=='f']

each of these dataframes A_Grade,B_Grade,C_Grade etc needs to be created in separate file with name A_Grade.csv,B_Grade.csv,C_Grade.csv. i wanted to use a for loop and pass the dataframe so to create it rather than writing separate lines to create the files as number of dataframe varies . This also sends msg using telegram bot.so the code snippet i tried is below. but it didnt work. in short the main thing is dynamically create the csv file with the dataframe name.

 for df in (A_Grade,B_Grade,C_Grade):
  if(len(df))
    dataframeitems.to_csv(f'C:\Documents\'+{df}+'{dt.date.today()}.csv',index=False)
    bot.send_message(chat_id=group_id,text='##{dfname.name} ##')

The solution given @Ynjxsjmh by work. Thanks @Ynjxsjmh. but i have another senario where in a function as below has dataframe passed as argument and the result on the dataframe needs to be saved as csv with dataframe name.

def func(dataframe):
  ...
  ...
  ...
  dataframe2=some actions and operations on dataframe
  result = dataframe2

result.to_csv(params.datafilepath+f'ResultFolder\{dataframe}_{dt.date.today()}.csv',index=False)

The file needs to be saved as per the name of the dataframe.csv

Answer 1

Your f-string is weird, you can use Series.unique() to get unique values in Series.

for grade in df['Grade'].unique():
    grade_df = df[df['Grade'].eq(grade)]
    grade_df.to_csv(f'C:\Documents\{grade.upper()}_Grade_{dt.date.today()}.csv', index=False)

Answer 2

I could get using below code

def get_df_name(df):
   name =[x for x in globals() if globals()[x] is df][0]
   return name

filename=get_df_name(dataframe)
print(filename)