Python Glob without the whole path - only the filename

Question

Is there a way I can use glob on a directory, to get files with a specific extension, but only the filename itself, not the whole path?

Answer 1

Use os.path.basename(path) to get the filename.

Answer 2

This might help someone:

names = [os.path.basename(x) for x in glob.glob('/your_path')]

Answer 3

map(os.path.basename, glob.glob("your/path"))

Returns an iterable with all the file names and extensions.

Answer 4

os.path.basename works for me.

Here is Code example:

import sys,glob
import os

expectedDir = sys.argv[1]                                                    ## User input for directory where files to search

for fileName_relative in glob.glob(expectedDir+"**/*.txt",recursive=True):       ## first get full file name with directores using for loop

    print("Full file name with directories: ", fileName_relative)

    fileName_absolute = os.path.basename(fileName_relative)                 ## Now get the file name with os.path.basename

    print("Only file name: ", fileName_absolute)

Output :

Full file name with directories:  C:\Users\erinksh\PycharmProjects\EMM_Test2\venv\Lib\site-packages\wheel-0.33.6.dist-info\top_level.txt
Only file name:  top_level.txt

Answer 5

I keep rewriting the solution for relative globbing (esp. when I need to add items to a zipfile) - this is what it usually ends up looking like.

# Function
def rel_glob(pattern, rel):
    """glob.glob but with relative path
    """
    for v in glob.glob(os.path.join(rel, pattern)):
        yield v[len(rel):].lstrip("/")

# Use
# For example, when you have files like: 'dir1/dir2/*.py'
for p in rel_glob("dir2/*.py", "dir1"):
    # do work
    pass

Answer 6

If you are looking for CSV file:

file = [os.path.basename(x) for x in glob.glob(r'C:\Users\rajat.prakash\Downloads//' + '*.csv')]

If you are looking for EXCEL file:

file = [os.path.basename(x) for x in glob.glob(r'C:\Users\rajat.prakash\Downloads//' + '*.xlsx')]

Answer 7

for f in glob.glob(gt_path + "/*.png"):  # find all png files
      exc_name = f.split('/')[-1].split(',')[0]

Then the exc_name is like myphoto.png

Answer 8

None of the existing answers mention using the new pathlib module, which is what I was searching for, so I'll add a new answer here.

Path.glob produces Path objects containing the full path including any directories. If you only need the file names, use the Path.name property.

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If you find yourself frequently converting between pathlib and os.path, check out this handy table converting functions between the two libraries.

Answer 9

Or using pathlib:

from pathlib import Path

dir_URL = Path("your_directory_URL") # e.g. Path("/tmp")
filename_list = [file.name for file in dir_URL.glob("your_pattern")]