'Python Tkinter GUI Calculator
So I am currently in the process of making a GUI Calculator, but am unsure on how to write code that will perform the operations of the calculator. Right now I currently have setup the window, entry box, and calculator buttons, but none of them actually do anything at the moment.
I am just confused on how these buttons are represented in code and so I am not sure how to write a block of code that will be able to read in these button inputs and perform addition,subtraction, etc.
Here is my code so far
class Calculator(Frame):
def __init__(self,master):
Frame.__init__(self,master)
self.grid()
self.dataEnt = Entry(self)
self.dataEnt.grid(row = 0, column = 1, columnspan = 4)
labels =[['AC','%','/'],
['7','8','9','*'],
['4','5','6','-'],
['1','2','3','+'],
['0','.','=']]
label = Button(self,relief = RAISED, padx = 10, text = labels[0][0]) #AC
label.grid(row = 1, column = 0, columnspan = 2)
label = Button(self,relief = RAISED, padx = 10, text = labels[0][1]) # %
label.grid(row = 1, column = 3)
label = Button(self,relief = RAISED, padx = 10, text = labels[0][2]) # /
label.grid(row = 1, column = 4)
for r in range(1,4):
for c in range(4):
#create label for row r and column c
label = Button(self,relief = RAISED,
padx = 10,
text = labels[r][c]) # 789* 456- 123+
# place label in row r and column c
label.grid(row = r+1, column = c+1)
label = Button(self,relief = RAISED, padx = 10, text = labels[4][0]) #0
label.grid(row = 5, column = 0, columnspan = 2)
label = Button(self,relief = RAISED, padx = 10, text = labels[4][1]) # .
label.grid(row = 5, column = 3)
label = Button(self,relief = RAISED, padx = 10, text = labels[4][2]) # =
label.grid(row = 5, column = 4)
def operations(self,num ):
def main():
root = Tk()
root.title('Calculator')
obj = Calculator(root)
root.mainloop()
and here is what the calculator looks like so far
My guess is that I need to somehow be able to read the input as a string and then have python evaluate that string as a mathematical expression but I am not sure how to go about it.
Thanks for any help!
Solution 1:[1]
What you could do is bind all buttons to a method that identifies the button and append a string to a list or evaluate the expression. This list could then be displayed in the label.
def button_press(self, event):
widget = event.widget
text = widget["text"]
if text != "AC" and text != "=":
self.operations.append(text)
elif text == "AC":
self.operations = [] # Clear the list.
elif text == "=":
self.evaluate()
self.label["text"] = "".join(self.operations)
def evaluate(self):
try:
self.operations = [str(eval("".join(self.operations)))]
except (ArithmeticError, SyntaxError, TypeError, NameError):
self.operations = ["ERROR"]
This code cannot just be pasted in to your program, it's just to demonstrate how you could solve the problem.
Solution 2:[2]
use simply pyautogui for basic GUI calculator
import math
import pyautogui
print( '+ =add |- =subtraction |* =multiplication | / =division |w =remainder of division |i =percentage |s =product of a number by itself \n'
'|p =prime number |r =square root')
def p(num):
for i in range(2, int(num)):
if int(num) % i == 0:
return i
return False
while True:
try:
try:
#----------------------------------------------------------#
num=float(pyautogui.prompt('1st','pcalculator'))
op=pyautogui.prompt('sign','pcalculator')
if not op == 'p':
nun=float(pyautogui.prompt('2nd','pcalculator'))
if op=='+':
x=pyautogui.confirm(num+nun,'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
elif op=='-':
x=pyautogui.confirm(num-nun,'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
elif op=='*':
x=pyautogui.confirm(num*nun,'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
elif op=='/':
x=pyautogui.confirm(num/nun,'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
elif op=='w':
x=pyautogui.confirm(num%nun,'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
elif op=='i':
x=pyautogui.confirm(num/nun*100,'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
elif op=='s':
x=pyautogui.confirm(num**nun,'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
elif op=='p':
if p(num):
x=pyautogui.confirm((int(num),'is a composite number'),'pcalculator',buttons=['Ok','Cancel'])
if x=='Cancel':
break
else:
x=pyautogui.confirm((int(num),'is a prime number'),'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
elif op=='r':
x=pyautogui.confirm(math.sqrt(num),'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
#-------------------------------------------------------------------#
except ZeroDivisionError:
x=pyautogui.confirm("Error: you can not divide by 0",'pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
except ValueError:
x=pyautogui.confirm('Invalid input,use only integers,decimals and symbols.','pcalculator ',buttons=['Ok','Cancel'])
if x=='Cancel':
break
Solution 3:[3]
Python Tkinter GUI Calculator without build in eval function
from tkinter import *
from tkinter import ttk
class SimpleCalculator (Tk):
def __init__(self):
super().__init__()
frame = ttk.Frame(self)
frame.grid(row=0, column=0, pady=(5, 5), padx=(5, 5))
self.entry_screen_value = StringVar()
self.screen_entry = ttk.Entry(frame, textvariable=self.entry_screen_value)
self.screen_entry.grid(row=0, column=0, columnspan=4, sticky=(W, E), pady=(5, 5))
# btn_square = ttk.Button(frame, text = "?x", command = press_square)
# btn_square.grid(row = 1, column = 0)
btn_delete = ttk.Button(frame, text=" C ", command = self.press_delete)
btn_delete.grid(row=2, column=3)
btn_9 = ttk.Button(frame, text=" 9 ", command= self.press_nine)
btn_9.grid(row=2, column=2)
btn_8 = ttk.Button(frame, text=" 8 ", command= self.press_eight)
btn_8.grid(row=2, column=1)
btn_7 = ttk.Button(frame, text=" 7 ", command= self.press_seven)
btn_7.grid(row=2, column=0)
btn_add = ttk.Button(frame, text=" + ", command=self.press_add)
btn_add.grid(row=3, column=3)
btn_6 = ttk.Button(frame, text=" 6 ", command=self.press_six)
btn_6.grid(row=3, column=2)
btn_5 = ttk.Button(frame, text=" 5 ", command=self.press_five)
btn_5.grid(row=3, column=1)
btn_4 = ttk.Button(frame, text=" 4 ", command=self.press_four)
btn_4.grid(row=3, column=0)
btn_sub = ttk.Button(frame, text=" - ", command=self.press_sub)
btn_sub.grid(row=4, column=3)
btn_3 = ttk.Button(frame, text=" 3 ", command=self.press_three)
btn_3.grid(row=4, column=2)
btn_2 = ttk.Button(frame, text=" 2 ", command=self.press_two)
btn_2.grid(row=4, column=1)
btn_1 = ttk.Button(frame, text=" 1 ", command=self.press_one)
btn_1.grid(row=4, column=0)
btn_multi = ttk.Button(frame, text=" * ", command=self.press_multi)
btn_multi.grid(row=5, column=3)
btn_0 = ttk.Button(frame, text=" 0 ", command=self.press_zero)
btn_0.grid(row=5, column=0, columnspan=2, sticky=(W, E))
btn_dot = ttk.Button(frame, text=" . ", command=self.press_dot)
btn_dot.grid(row=5, column=2)
btn_divide = ttk.Button(frame, text=" ÷ ", command=self.press_divide)
btn_divide.grid(row=6, column=3)
btn_equal = ttk.Button(frame, text=" = ", command=self.Press_equal)
btn_equal.grid(row=6, column=0, columnspan=3, sticky=(W, E))
self.mainloop()
def press_zero(self):
self.screen_entry.insert(END, "0")
def press_one(self):
self.screen_entry.insert(END, "1")
def press_two(self):
self.screen_entry.insert(END, "2")
def press_three(self):
self.screen_entry.insert(END, "3")
def press_four(self):
self.screen_entry.insert(END, "4")
def press_five(self):
self.screen_entry.insert(END, "5")
def press_six(self):
self.screen_entry.insert(END, "6")
def press_seven(self):
self.screen_entry.insert(END, "7")
def press_eight(self):
self.screen_entry.insert(END, "8")
def press_nine(self):
self.screen_entry.insert(END, "9")
def press_dot(self):
self.screen_entry.insert(END, ".")
def press_delete(self):
val = self.entry_screen_value.get()[:-1]
self.screen_entry.delete(0, END)
self.screen_entry.insert(END, val)
def press_add(self):
self.screen_entry.insert(END, "+")
def press_sub(self):
self.screen_entry.insert(END, "-")
def press_multi(self):
self.screen_entry.insert(END, "*")
def press_divide(self):
self.screen_entry.insert(END, "÷")
def press_square(self):
self.screen_entry.insert(END, "?(")
def Press_equal(self):
formula = self.doMultiFirst(self.do_divide_first(self.convertTo(self.entry_screen_value.get())))
result = 0
temp = 0
sign = ""
if len(formula) == 1:
result = formula[0]
else:
for di in formula:
if di != "+" and di != "*" and di != "-" and di != "÷":
if sign == "+":
temp = float(di)
result += temp
elif sign == "-":
temp = float(di)
result -= temp
elif sign == "*":
temp = int(di)
result *= temp
elif sign == "÷":
temp = float(di)
result /= temp
else:
temp = float(di)
result = temp
else:
if di == "+":
sign = "+"
elif di == "-":
sign = "-"
elif di == "*":
sign = "*"
elif di == "÷":
sign = "÷"
self.screen_entry.delete(0, END)
r = str(result).split(".")[-1:]
if r[0] == '0':
self.screen_entry.insert(END, int(result))
else:
self.screen_entry.insert(END, result)
print(formula)
# this function convert formula = "-1+11+3+5*5" to ['-1','+','11','+','3','+','5','*','5']
def convertTo(self, nm):
# this temp list we store our formula in it
dd = []
temp = ""
for i in range(len(nm)):
if nm[i] != "+" and nm[i] != "*" and nm[i] != "÷" and nm[i] != "-":
temp += nm[i]
else:
# if our first input is -1 we need to combine it we second input and ill be like -1
if i == 0 and nm[0] == "-":
temp = "-"
else:
# we add prev combination like 11 to the list after we reach sign + or * or ..
dd += [temp]
dd += [nm[i]]
temp = ""
if i == len(nm) - 1:
dd += [temp]
return dd
# this function convert ['3','+','4','*','2','+','3'] to ['3','+','8','+','3']
def doMultiFirst(self, ls):
newlist = []
for i in range(len(ls)):
if ls[i] == "*":
f = float(ls[i - 1])
l = float(ls[i + 1])
r = f * l
ls[i + 1] = r
ls[i] = 0
ls[i - 1] = 0
for k in ls:
if k != 0:
newlist += [k]
return newlist
# this function convert ['3','+','4','÷','2','+','3'] to ['3','+','2','+','3']
def do_divide_first(self, ls):
newlist = []
for i in range(len(ls)):
if ls[i] == "÷":
f = float(ls[i - 1])
l = float(ls[i + 1])
r = f / l
ls[i + 1] = r
ls[i] = 0
ls[i - 1] = 0
for k in ls:
if k != 0:
newlist += [k]
return newlist
if __name__ == "__main__":
SimpleCalculator()
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Ted Klein Bergman |
| Solution 2 | Aditya Kumar |
| Solution 3 |