'Rank actors with movies released in India based on their average ratings. Which actor is at the top of the list?
-- Note: The actor should have acted in at least five Indian movies. -- (Hint: You should use the weighted average based on votes. If the ratings clash, then the total number of votes should act as the tie breaker
SELECT n.name as actor_name
, r.total_votes
, COUNT(r.movie_id) as movie_count
, r.avg_rating as actor_avg_rating
, RANK() OVER( PARTITION BY
rm.category = 'actor'
ORDER BY
r.avg_rating DESC
) actor_rank
FROM names as n
JOIN role_mapping as rm
ON n.id = rm.movie_id
JOIN movie as m
ON m.id = rm.movie_id
JOIN ratings as r
ON r.movie_id = m.id
where m.country regexp '^INDIA$'
and m.languages regexp '^HINDI$'
group
by actor_name
having count(rm.movie_id) >= 5;
The output gives no error but no result too.
Solution 1:[1]
This would work:
SELECT a.name as actor_name, c.total_votes, COUNT(c.movie_id) as movie_count,c.avg_rating as actor_avg_rating,
RANK() OVER( PARTITION BY
d.category = 'actor'
ORDER BY
c.avg_rating DESC
) actor_rank
FROM names a, movie b, ratings c, role_mapping d
where b.country = 'INDIA'
and b.id = c.movie_id
and b.id= d.movie_id
and a.id = d.name_id
group by actor_name
having count(d.movie_id) >= 5
order by actor_avg_rating desc
;
You had tried joining nameid with movie id which is the mistake
Solution 2:[2]
SELECT NAME AS actor_name,
Cast(Sum(total_votes)/Count(movie_id) AS DECIMAL(8,0)) AS total_votes,
Count(movie_id) AS movie_count,
avg_rating AS actor_avg_rating,
Dense_rank() OVER(ORDER BY avg_rating DESC) AS actor_rank
FROM names n INNER JOIN role_mapping r ON n.id=r.name_id
INNER JOIN ratings using (movie_id) INNER JOIN movie m ON m.id=r.movie_id
WHERE country="india" AND category="actor"
GROUP BY actor_name
HAVING Count(movie_id)>=5;
Solution 3:[3]
WITH top_actor
AS (SELECT b.NAME
AS
actor_name,
Sum(c.total_votes)
AS
total_votes,
Count(DISTINCT a.movie_id)
AS
movie_count,
Round(Sum(c.avg_rating * c.total_votes) / Sum(c.total_votes), 2)
AS
actor_avg_rating
FROM role_mapping a
INNER JOIN names b
ON a.name_id = b.id
INNER JOIN ratings c
ON a.movie_id = c.movie_id
INNER JOIN movie d
ON a.movie_id = d.id
WHERE a.category = 'actor'
AND d.country LIKE '%India%'
GROUP BY a.name_id,
b.NAME
HAVING Count(DISTINCT a.movie_id) >= 5)
SELECT *,
Rank()
OVER (
ORDER BY actor_avg_rating DESC) AS actor_rank
FROM top_actor;
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | zhisme |
Solution 2 | |
Solution 3 | cigien |