'React Toggle open and close using onclick on map function
I have an onClick
in map function, if I click onClick
it will change state of all map item not that item which I clicked. I am using useState
hook.
const [open, setOpen] = useState(true);
{
FilterAvailable.map((item, id) => {
return (
<li className="filterItem">
<div
className="filterBtn flex align-center justify-between"
onClick={() => setOpen(!open)}
>
<h2>{item.catogery}</h2>
<div>
{open ? (
<IoIosArrowDown className="downArrow" />
) : (
<IoIosArrowUp className="downArrow" />
)}
</div>
</div>
{item.options.map(option => {
return (
<>
{open && (
<ul className="filterOption">
<li className="filterOptionitem">
<button>{option}</button>
</li>
</ul>
)}
{/* <div className="hrLine"></div> */}
</>
);
})}
</li>
);
});
}
I want to open only those item option which click.
Solution 1:[1]
Put the index inside state on onclick , inside map check if state index equals to map index and you are done
Solution 2:[2]
Your state is in the wrong place, you need to break the component and have a open state per filterableItem
const Filters = () => {
return FilterAvailable.map((item, id) => {
return <FilterItem item={item} />;
});
};
const FilterItem = ({ item }) => {
const [open, setOpen] = useState(true);
return (
<li className="filterItem">
<div
className="filterBtn flex align-center justify-between"
onClick={() => setOpen(!open)}
>
<h2>{item.catogery}</h2>
<div>
{open ? (
<IoIosArrowDown className="downArrow" />
) : (
<IoIosArrowUp className="downArrow" />
)}
</div>
</div>
{item.options.map(option => {
return (
<>
{open && (
<ul className="filterOption">
<li className="filterOptionitem">
<button>{option}</button>
</li>
</ul>
)}
</>
);
})}
</li>
);
};
Solution 3:[3]
Consider moving the mapped elements to their own component with props - then you create and set your open and closed state there.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | n1koloza |
Solution 2 | Shujaat |
Solution 3 | coderMatt |