'Requests format for uploading multiple images in FastAPI
Example
Here's my code trying to upload a list of images:
import requests
import glob
import cv2
path = glob.glob("test_folder/*", recursive=True) # a list of image's path
lst_img = []
for p in path[:3]:
# img = cv2.imread(p)
lst_img.append((p, open(p, 'rb'), "image/jpeg"))
data = {"files": lst_img}
url = "http://localhost:6789/" # url api of app
res = requests.post(url=url, data=data)
print(res.status_code)
print(res.text)
Description
I am trying to upload a list of images through Python requests (package) to a FastAPI endpoint, but maybe my request's format is wrong, leading to a 422
error:
"detail":[{"loc":["body","files",0],"msg":"Expected UploadFile, received: <class 'str'>","type":"value_error"}
This is my request's format:
{'files': [('test_folder/image77.jpeg', <_io.BufferedReader name='test_folder/image77.jpeg'>, 'image/jpeg'), ('test_folder/image84.jpeg', <_io.BufferedReader name='test_folder/image84.jpeg'>, 'image/jpeg'), ('test_folder/image82.jpeg', <_io.BufferedReader name='test_folder/image82.jpeg'>, 'image/jpeg')]}
I've tried many ways, but always fails. Many thank if u guys help to solve it.
Environment
- OS: Linux: (Ubuntu 18.04)
- FastAPI Version: 0.61.1
- Requests Version: 2.24.0
- Python Version: 3.7.5
I tried the below, but still not working:
lst_img.append(("file", (p, open(p, 'rb'), "image/jpeg")))
My FastAPI main.py
from typing import List
from fastapi import FastAPI, File, UploadFile
from fastapi.responses import StreamingResponse, FileResponse
app = FastAPI()
@app.post("/")
async def main(files: List[UploadFile] = File(...)):
# file_like = open(video_path, mode="rb")
# return StreamingResponse(file_like, media_type="video/mp4")
return {"filenames": [file.filename for file in files]}
Solution 1:[1]
Below is an example of how to upload multiple files (images) using Python requests and FastAPI. If you need to send additional data when uploading the files, please have a look here. Also, if you need async
writing for saving the images on server side, please have a look at this answer.
app.py
import uvicorn
from fastapi import File, UploadFile, FastAPI
from typing import List
app = FastAPI()
@app.post("/upload")
async def upload(files: List[UploadFile] = File(...)):
for file in files:
try:
contents = await file.read()
with open(file.filename, 'wb') as f:
f.write(contents)
except Exception:
return {"message": "There was an error uploading the file(s)"}
finally:
await file.close()
return {"message": f"Successfuly uploaded {[file.filename for file in files]}"}
if __name__ == '__main__':
uvicorn.run(app, host='0.0.0.0', port=8000)
test.py
import requests
import glob
paths = glob.glob("images/*", recursive=True) # returns a list of file paths
images = [('files', open(p, 'rb')) for p in paths] # or paths[:3] to select the first 3 images
url = 'http://127.0.0.1:8000/upload'
resp = requests.post(url=url, files=images)
print(resp.json())
Solution 2:[2]
You should be using the files
argument for request
module to send a file
import requests
import glob
path = glob.glob("test_folder/*", recursive=True) # a list of image's path
lst_img = []
for p in path[:3]:
lst_img.append({"files": open(p, 'rb')})
url = "http://localhost:6789/" # url api of app
for data in lst_img:
res = requests.post(url=url, files=data)
print(res.status_code)
print(res.text)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | clamentjohn |