'Scanning multiple lines using single scanner object

I a newbie to java so please don't rate down if this sounds absolute dumb to you

ok how do I enter this using a single scanner object

5

hello how do you do

welcome to my world

6 7

for those of you who suggest 

scannerobj.nextInt->nextLine->nextLine->nextInt->nextInt,,,

check it out, it does not work!!!

thanks

javainputoutputjava.util.scanner


Solution 1:[1]

public static void main(String[] args) {
    Scanner  in    = new Scanner(System.in);

    System.out.printf("Please specify how many lines you want to enter: ");        
    String[] input = new String[in.nextInt()];
    in.nextLine(); //consuming the <enter> from input above

    for (int i = 0; i < input.length; i++) {
        input[i] = in.nextLine();
    }

    System.out.printf("\nYour input:\n");
    for (String s : input) {
        System.out.println(s);
    }
}

Sample execution: 

Please specify how many lines you want to enter: 3
Line1
Line2
Line3

Your input:
Line1
Line2
Line3

Solution 2:[2]

public class Sol{

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in); 

       while(sc.hasNextLine()){

           System.out.println(sc.nextLine());
       }

    }
}

Solution 3:[3]

By default, the scanner uses space as a delimiter. In order to scan by lines using forEachRemaining, change the scanner delimiter to line as below.

public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);
    scanner.useDelimiter("\n");
    scanner.forEachRemaining(System.out::println);
}

Solution 4:[4]

try this code 

Scanner  in    = new Scanner(System.in);

System.out.printf("xxxxxxxxxxxxxxx ");        
String[] input = new String[in.nextInt()];

for (int i = 0; i < input.length; i++) {
    input[i] = in.nextLine();
}

for (String s : input) {
    System.out.println(s);
}

Solution 5:[5]

You can try only with lambda too:

public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);
    scanner.forEachRemaining(input -> System.out.println(input));
}

Solution 6:[6]

    public static void main(String[] args) {
       Scanner console = new Scanner(System.in);
     
        int first = console.nextInt();
        String second = console.nextLine();
        String third = console.nextLine();
        int fourth = console.nextInt();

        System.out.println(first);
        System.out.println(second);
        System.out.println(third);
        System.out.println(fourth);
}

so you get them in line by line

Solution 7:[7]

may be we can use this approach:

for(int i = 0; i < n; i++)
   {
       Scanner sc1 = new Scanner(System.in);
       str0[i] = sc1.nextLine();
       System.out.println(str0[i]);
   }

that is we create the scanner object every time before we read the nextLine. :)

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 ifloop
Solution 2
Solution 3
Solution 4 Jay kumar
Solution 5 Jouberto Fonseca
Solution 6 Ignatiy Kruglov
Solution 7 Sudarshan

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