'Select option from dropdown menu with PHP and mySql

I tried to create a simple select dropdown menu from MySQL database. However, it does not work on my code.

Here is my code: 

            <?php
              mysql_select_db($database_conn, $conn);
              $query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
              $RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
              $totalRows_RsCourse = mysql_num_rows($RsCourse);
              $count=0;
              while ( $row = mysql_fetch_array($RsCourse, MYSQL_ASSOC)) {
              $courseid=$row["courseid"];
         $count++;  
              }
             ?>

            <tr>
            <td bgcolor="#CCCCCC">&nbsp;Course Name</td>
            <td bgcolor="#dfdfdf">&nbsp;<select name="courseid">
            <option value="" SELECTED>Selected Course</option>      
            <option value="<?php echo $courseid; ?>"><?php echo $row_RsCourse['$courseid']; ?></option>
            </select>
            </td>
            </tr>

Any advice will be appreciated!

phpmysqlselectdrop-down-menuoption


Solution 1:[1]

 <?php

 echo '<tr>
        <td bgcolor="#CCCCCC">&nbsp;Course Name</td>
        <td bgcolor="#dfdfdf">&nbsp;';

        mysql_select_db($database_conn, $conn);
        $query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
        $RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
        $totalRows_RsCourse = mysql_num_rows($RsCourse);
        if($totalRows_RsCourse)
        {
        echo '<select name="courseid"><option value="" SELECTED>Selected Course</option>';
            $count=0;

            while ($row = mysql_fetch_array($RsCourse, MYSQL_ASSOC))
            {
            $count++;
            echo '<option value="'.$row['courseid'].'">'.$row['courseid'].'</option>';
            }
            echo '</select>';
        }
        else
        {
        echo 'No courses to show yet.'; // no rows in tbl_course
        }
        echo '</td>
            </tr>';

?>

That was a mess, but hope you can go on from these new codes. Enjoy.

PS: this part >'.$row['courseid'].'</option> u can change to new one according to your table structure which one is not shown here.

<?php

 echo '<tr>
        <td bgcolor="#CCCCCC">&nbsp;Course Name</td>
        <td bgcolor="#dfdfdf">&nbsp;';

        mysql_select_db($database_conn, $conn);
        $query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
        $RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
        $totalRows_RsCourse = mysql_num_rows($RsCourse);


        echo '<select name="courseid"><option value="" SELECTED>Selected Course</option>';
            $count=0;

            while ($row = mysql_fetch_array($RsCourse, MYSQL_ASSOC))
            {
            $count++;
            echo '<option value="'.$row['courseid'].'">'.$row['courseid'].'</option>';
            }
            echo '</select></td>
            </tr>';

?>

Solution 2:[2]

You can store everything in a buffer and print at once in the select below: 

    <?php
      mysql_select_db($database_conn, $conn);
      $query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
      $RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
      $coursesHtml = "";
      while ( $row = mysql_fetch_array($RsCourse, MYSQL_ASSOC)) {
        $coursesHtml .= "<option value='{$row["courseid"]}'>{$row["coursename"]}</option>";
      }
     ?>

    <tr>
    <td bgcolor="#CCCCCC">Course Name</td>
    <td bgcolor="#dfdfdf">
    <select name="courseid">
    <option value="" SELECTED>Selected Course</option>      
    <?= $coursesHtml  ?>
    </select>
    </td>
    </tr>

PS: Avoid use &nbsp; , style your html well with css using padding-left: 5px; or other features;

PS2: You should not show your page/form with tables structure, use divs with flexbox.

Sources

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Source: Stack Overflow

Solution Source
Solution 1
Solution 2 capcj

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