'What is the best way to sum arrays using ECMASCRIPT 6 Generator/Functions
Is there a better way instead of adding values of arrays up using a generator function as closure?
var sumArrays = function(){
var sum = 0;
return function*(){
while(true){
var array = yield sum;
if(array.__proto__.constructor === Array){
sum += array.reduce(function(val,val2){ return val+val2; });
}
else sum=0;
}
};
};
var gen = sumArrays();
// is this step required to make a generator or could it be done at least differently to spare yourself from doing this step?
gen = gen();
// sum some values of arrays up
console.log('sum: ',gen.next()); // Object { value=0, done=false}
console.log('sum: ',gen.next([1,2,3,4])); // Object { value=10, done=false}
console.log('sum: ',gen.next([6,7])); // Object { value=23, done=false}
// reset values
console.log('sum: ',gen.next(false)); // Object { value=0, done=false}
console.log('sum: ',gen.next([5])); // Object { value=5, done=false}
Solution 1:[1]
This doesn't seem to be a problem generators are supposed to solve, so I would not use a generator here.
Directly using reduce
(ES5) seems to be more appropriate:
let sum = [1,2,3,4].reduce((sum, x) => sum + x);
As a function:
function sum(arr) {
return arr.reduce((sum, x) => sum + x);
}
If you really want to sum multiple arrays across multiple function calls, then return a normal function:
function getArraySummation() {
let total = 0;
let reducer = (sum, x) => sum + x;
return arr => total + arr.reduce(reducer);
}
let sum = getArraySummation();
console.log('sum:', sum([1,2,3])); // sum: 6
console.log('sum:', sum([4,5,6])); // sum: 15
Keep it simple.
Solution 2:[2]
Here is use of for/of loop and arrow function,
const sumArray = myArray => {
let sum = 0;
for(const value of myArray)
sum+= value;
return sum;
}
const myArray = [1, 2, 5];
console.log(sumArray(myArray));
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | Mayur |