'What is the difference between exit and return?
What is difference between return and exit statement in C programming when called from anywhere in a C program?
Solution 1:[1]
- return returns from the current function; it's a language keyword like
for
orbreak
. - exit() terminates the whole program, wherever you call it from. (After flushing stdio buffers and so on).
The only case when both do (nearly) the same thing is in the main()
function, as a return from main performs an exit()
.
In most C implementations, main
is a real function called by some startup code that does something like int ret = main(argc, argv); exit(ret);
. The C standard guarantees that something equivalent to this happens if main
returns, however the implementation handles it.
Example with return
:
#include <stdio.h>
void f(){
printf("Executing f\n");
return;
}
int main(){
f();
printf("Back from f\n");
}
If you execute this program it prints:
Executing f Back from f
Another example for exit()
:
#include <stdio.h>
#include <stdlib.h>
void f(){
printf("Executing f\n");
exit(0);
}
int main(){
f();
printf("Back from f\n");
}
If you execute this program it prints:
Executing f
You never get "Back from f". Also notice the #include <stdlib.h>
necessary to call the library function exit()
.
Also notice that the parameter of exit()
is an integer (it's the return status of the process that the launcher process can get; the conventional usage is 0 for success or any other value for an error).
The parameter of the return statement is whatever the return type of the function is. If the function returns void, you can omit the return at the end of the function.
Last point, exit()
come in two flavors _exit()
and exit()
. The difference between the forms is that exit()
(and return from main) calls functions registered using atexit()
or on_exit()
before really terminating the process while _exit()
(from #include <unistd.h>
, or its synonymous _Exit from #include <stdlib.h>
) terminates the process immediately.
Now there are also issues that are specific to C++.
C++ performs much more work than C when it is exiting from functions (return
-ing). Specifically it calls destructors of local objects going out of scope. In most cases programmers won't care much of the state of a program after the processus stopped, hence it wouldn't make much difference: allocated memory will be freed, file ressource closed and so on. But it may matter if your destructor performs IOs. For instance automatic C++ OStream
locally created won't be flushed on a call to exit and you may lose some unflushed data (on the other hand static OStream
will be flushed).
This won't happen if you are using the good old C FILE*
streams. These will be flushed on exit()
. Actually, the rule is the same that for registered exit functions, FILE*
will be flushed on all normal terminations, which includes exit()
, but not calls to _exit()
or abort().
You should also keep in mind that C++ provide a third way to get out of a function: throwing an exception. This way of going out of a function will call destructor. If it is not catched anywhere in the chain of callers, the exception can go up to the main() function and terminate the process.
Destructors of static C++ objects (globals) will be called if you call either return
from main()
or exit()
anywhere in your program. They wont be called if the program is terminated using _exit()
or abort()
. abort()
is mostly useful in debug mode with the purpose to immediately stop the program and get a stack trace (for post mortem analysis). It is usually hidden behind the assert()
macro only active in debug mode.
When is exit() useful ?
exit()
means you want to immediately stops the current process. It can be of some use for error management when we encounter some kind of irrecoverable issue that won't allow for your code to do anything useful anymore. It is often handy when the control flow is complicated and error codes has to be propagated all way up. But be aware that this is bad coding practice. Silently ending the process is in most case the worse behavior and actual error management should be preferred (or in C++ using exceptions).
Direct calls to exit()
are especially bad if done in libraries as it will doom the library user and it should be a library user's choice to implement some kind of error recovery or not. If you want an example of why calling exit()
from a library is bad, it leads for instance people to ask this question.
There is an undisputed legitimate use of exit()
as the way to end a child process started by fork() on Operating Systems supporting it. Going back to the code before fork() is usually a bad idea. This is the rationale explaining why functions of the exec() family will never return to the caller.
Solution 2:[2]
I wrote two programs:
int main(){return 0;}
and
#include <stdlib.h>
int main(){exit(0)}
After executing gcc -S -O1
. Here what I found watching
at assembly (only important parts):
main:
movl $0, %eax /* setting return value */
ret /* return from main */
and
main:
subq $8, %rsp /* reserving some space */
movl $0, %edi /* setting return value */
call exit /* calling exit function */
/* magic and machine specific wizardry after this call */
So my conclusion is: use return
when you can, and exit()
when you need.
Solution 3:[3]
In C, there's not much difference when used in the startup function of the program (which can be main()
, wmain()
, _tmain()
or the default name used by your compiler).
If you return
in main()
, control goes back to the _start()
function in the C library which originally started your program, which then calls exit()
anyways. So it really doesn't matter which one you use.
Solution 4:[4]
the return statement exits from the current function and exit() exits from the program
they are the same when used in main() function
also return is a statement while exit() is a function which requires stdlb.h header file
Solution 5:[5]
For the most part, there is no difference in a C program between using return
and calling exit()
to terminate main()
.
The time when there is a difference is if you've created code that will be executed after you return from main()
that relies on variables local to main()
. One way that manifests itself is with setvbuf()
:
int main(void)
{
char buffer[BUFSIZ];
setvbuf(stdout, buffer, _IOFBF, BUFSIZ);
…code using stdout…
return 0;
}
In this example, the buffer provided via setvbuf()
goes out of scope when main()
returns, but the code that flushes and closes stdout
will be attempting to use that buffer. This leads to undefined behaviour.
The other mechanism is to invoke atexit()
with a function that accesses data from main()
— via a pointer. This is harder to set up as the functions called via the atexit()
mechanism are not given any arguments. So, you have to do something like this:
static void *at_exit_data = 0;
static void at_exit_handler(void)
{
char *str = at_exit_data;
printf("Exiting: %s\n", str);
}
int main(void);
{
char buffer[] = "Message to be printed via functions registered with at_exit()";
at_exit_data = buffer;
at_exit(at_exit_handler);
…processing…
return 0;
}
Again, the buffer pointed at by at_exit_data
has ceased to exist when the program returned from main()
and so the handler function invokes undefined behaviour.
There is a related function, at_quick_exit()
, but the functions registered with it are only called if the quick_exit()
function is called, which precludes the functions being called after main()
returns.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Peter Cordes |
Solution 2 | hurufu |
Solution 3 | |
Solution 4 | kapil |
Solution 5 | Jonathan Leffler |