Why Is My Image Not Recognized In Python?

Question

I wrote this code:

from tkinter import *
from locate import this_dir

path = str(this_dir())

print(path + "\\BGnew.png")

window = Tk()
window.geometry("480x480")
window.title("CodeHook - Start Menu")
ico = PhotoImage(file = path + "\\icon.png")
bg = PhotoImage(file = path + "\\BGnew.png")

window.iconphoto(True, ico)

c=Canvas(window,bg="gray16",height=200,width=200)
filename=PhotoImage(file= bg)
background_label=Label(window,image=filename)
background_label.place(x=0,y=0,relwidth=1,relheight=1)


new_workspace = Button(window, text = "New Workspace", font = ("", 13))

new_workspace.pack()

window.mainloop()

When An Error Occured:

Traceback (most recent call last): File "c:\Users\Dani\Desktop\Code\Python\CodeHook\main.py", line 17, in filename=PhotoImage(file= bg) File "C:\Users\Dani\AppData\Local\Programs\Python\Python39\lib\tkinter_init_.py", line 4064, in init Image.init(self, 'photo', name, cnf, master, **kw) File "C:\Users\Dani\AppData\Local\Programs\Python\Python39\lib\tkinter_init_.py", line 4009, in init self.tk.call(('image', 'create', imgtype, name,) + options) _tkinter.TclError: couldn't open "pyimage2": no such file or directory

Here Is My Folder Structure:

Code

    Python

        CodeHook

            BGnew.png

            icon.png

            main.py (file in which error occured)

Python Version: 3.9.7 IDE: Visual Studio Code (User)

Answer 1

You already have a PhotoImage object in bg variable. So you can remove line filename=PhotoImage(file= bg) and modify background_label=Label(window,image=filename) to background_label=Label(window,image=bg).

Small addition: you can use os.getcwd() to get current directory. Also it is a bad practice to concatenate path and filename, you can use os.path.join() to do that.