'Assign the result of a loop to a variable in Python

Consider a list I want to parse using a for :

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
for i in friends:
   print i

will return :

"Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"

However, if I want to put it to a (str) variable, like :

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
for i in friends:
    var=i

first I have to declare another var variable, which is silly but whatever. then,

print var

will return the last element of the list, which is "Paris", because the variable is overwritten for each iteration right.

So my question is : how can I assign the output of my loop "i", for each iteration, to a variable in Python ?

Sorry for the sillyness of this question but this is a concept I can't seem to figure out clearly.

Solution 1:^[1]

If I understand well, you'd like to dynamically create variables. Here it is.

from collections import OrderedDict

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
d = OrderedDict()
for idx, value in enumerate(friends):
    key = 'var' + str(idx)
    d[key] = value 

print(d)
# Output
OrderedDict([('var0', 'Joe'), ('var1', 'Zoe'), ('var2', 'Brad'), ('var3', 'Angelina'), ('var4', 'Zuki'), ('var5', 'Thandi'), ('var6', 'Paris')])

Solution 2:^[2]

I also have this question, this is how I managed to solve it somewhat:

    friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]

    new_friends = ' '.join([x for x in friends])

    print(new_friends)

Will return:

    Joe Zoe Brad Angelina Zuki Thandi Paris

Solution 3:^[3]

var = ''
friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
for i in friends:
    var=i

if list and loop are in function then declare var as global

global var

in starting of function

Solution 4:^[4]

If you want to join the values in friends into a comma-separated string, that would be

s = ','.join(friends)

If you want to include quotes around the names, maybe something like

s = ','.join(['"{0}"'.format(x) for x in friends])

Solution 5:^[5]

Try this at the end of the loop:

the_variable = the_variable + i

However, if you are to do this, you should add a space to the end of every item in the dictionary, otherwise it will output:

JoeZoeBradAngelinaZukiThandiParis

Solution 6:^[6]

I would use a dictionary instead, as I too spent a while looking into this, and determined that a dictionary would be easy enough.

    friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
    dict= {}
    for i in friends:
       dict[i] = i

    print(dict)
    print(dict['Zuki'])
    dict['Zuki'] = "Tim Smith"

    print(dict['Zuki'])

The Other option would be to just call the number:

    print(friends[0])

As for automatic assignment I haven't found a way to do it.

Solution 7:^[7]

I think the easiest & cleanest way for you would be a "List Comprehension", see here.

Here is the respective code:

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]      
var = [(i) for i in friends]

Should do what you want, right?

Sources

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Source: Stack Overflow

Solution	Source
Solution 1	SparkAndShine
Solution 2	e71az
Solution 3	hb X
Solution 4	tripleee
Solution 5	CheezBiscuit
Solution 6	Dayantat
Solution 7

'Assign the result of a loop to a variable in Python

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