def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
elixir-iex
python-3.6
query-optimization
asp.net-webhooks
wicketstuff
google-workspace-add-ons
referer
protected
marp
ggvis
gattlib
getstream-chat
createbitmap
bbc-micro
opensc
shader
spring-jdbc
text-justify
ionic2
pulumi-azure
flutter-gridview
google-data-catalog
keyboard-shortcuts
react-context
mass-assignment
value-iteration
dummy-variable
mailing
datatable-buttons
quarkus-caching