def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
robotics
ppl
rtcp
minimagick
formulas
flare
ibm-case-manager
android-studio-bumblebee
flutter-2
xcuitest
dotnetnuke
kali-linux
ebco
weblogic12c
surf
wowchemy
dllmain
executable
uigravitybehavior
service-reference
sonarlint
ora-00905
safemoon
capitalize
alpn
avurlasset
splunk-calculation
htf
characteristics
mako