def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
flooding
kitti
slowdown
android-appwidget
maven-repository
foundry-code-workbooks
runatserver
unminify
pythomnic3k
direct3d
tinymce-rails
x-cart
event-id
ruby-module
pycountry-convert
google-fitness-api
ddd-service
prototypal-inheritance
multivariate-analysis
mutators
flutter-borderdecoration
sql-to-linq-conversion
memory-profiling
b-lang
ie-compatibility-mode
pg-cron
window.onunload
getforegroundwindow
opayo
babel-parser