def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
ftdi
sap-cloud-foundry
vvv-wordpress
hibernate-session
ensjs
dwr
star-schema-datawarehouse
blazor-validation
coefplot
msbuild-itemgroup
mbf
watir-webdriver
duostack
neo4j-aura
combinatory-logic
one-class-classification
azure-rm
materialdesigntoolkit
turnjs
winston
azure-devops-extensions
forticlient
aws-sdk-java-2.0
rspamd
microstack
material-ui-x
time-t
sector
flutter-module
armv8