def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
xamarin.forms.entry
aztec-barcode
doc
httpbackend
bamboo
stream-cipher
psr-4
rome
jqmodal
binary-serialization
uifont
sixel
umbraco7
data-modeling
xcode11.4
swiftui-scrollview
clearml
restriction
smtp-oauth
solr-search
coingecko-api
django-socialauth
bloomberg
loop-counter
action-mailbox
tomcat8.5
touchablewithoutfeedback
nomachine
thunderbird-webextensions
shift-jis