def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
r-recipes
stack-trace
angular-storybook
facial-identification
v4l
embedded-linux
miracast
bigdl
python-responses
clang-tidy
ggmosaic
icollectionview
react-table-v6
attributes
chakracore
dynamics-crm-online
boost-python
cuteeditor
rasa-sdk
drop-duplicates
mips64
dotliquid
strapi
qtest
sentinel2
react-ga
subscript
navigationcontroller
flutter-video-player
table-plus