z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
ienumerable
mod-lua
rxjs
desolve
subsystem
tablesort
handlebarshelper
ember-data
office365-rest-client
sat4j
draftjs
wkhttpcookiestore
twitter-typeahead
erpnext
proxy-authentication
dependent-name
pbxproj
timing-diagram
.net-core-publishsinglefile
python-daemon
protected-questions
robotframework-swinglibrary
exception-safety
django-middleware
buybutton.js
changelog
facebook-pixel-helper
apache-camel-k
struts-tags
qgraphicsrectitem