z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
excel-2007
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reality-converter
com-interface
invoices
xor
git-diff
accord.net
handsontable
styled-components
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ios-permissions
propel
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cellspacing
wkwebview
fedex
hardware
afx
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vim-registers
except
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ussd
yq
request.financial
kanban
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asynctest