z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
openfaces
uglifyjs
opencv3.2
spdlog
catch2
itable
obs
rack-mini-profiler
webmail
threshold
pry-rails
pooling
friend-function
payment-method
amazon-cloudformation">amazon-cloudformation
viewdidlayoutsubviews
finalization
serenity-platform
concat
tcpdump
picturebox
path-manipulation
viewaction
bisection
poller
ryu
color-blindness
c3.js
async-pipe
npmrc