z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
sql-server-group-concat
hosts
interface-design
kubernetes-deployment
google-data
ng-modules
operator-overloading
swiftui-actionsheet
strophe
phlivephoto
array-key
free-jqgrid
wmdc
xstate-react
imagej-macro
manova
file-system-access-api
jsonpath-ng
foreign-collection
azure-devops-multistage-pipeline
utf-7
kibana
visualize
pyml
site-search
obiee
ber
yaws
visual-foxpro
apple-developer