z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
bloom-filter
sql-server-data-tools
smtp-oauth
libv8
sessionfactory
file-io
android-multi-display
msmessagetemplatelayout
npm-run
maven-bom
tin-can-api
prebid.js
poe
nspersistentcloudkitcontainer
cpu-cores
inbound-security-rule
fibonacci-heap
jira-agile
ionic-serve
opencv-text
sliver-grid
kismet-wireless
struts2-rest-plugin
openstack-keystone
timedelta
friend-class
datagridview
httpbackend
odoo-13
mallet