z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
mysql2
interact.js
preprocessor
cyclic-graph
vue-material
service-locator
json-serializable
y86
tuist
njs
rsconnect
lit-html
aptitude
circe
jailbreak
fontmetrics
flutter-notification
asp.net-core-viewcomponent
ini
selenoid
ocpsoft-rewrite
git-show
powerapps-makerportal
draw2d
ggtitle
imessage-extension
laravel-pagination
fullscreenchange
parser-generator
analyzer