z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
run-length-encoding
center-align
component-store
qcachegrind
angular9
igraph
acts-as-tenant
object-slicing
radix-sort
assemblies
nohup
url-rewrite-module
supportmapfragment
interlocked
logical-foundations
innertext
android-api-30
patch-package
unboxing
swiftpm
netflix-nebula-plugins
equation-solving
smalldatetime
boost-pool
android-package-managers
collision
idioms
choicefield
frame-pointer
privateobject.invoke