z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
rterm
mercurial-evolve
hybrid
isort
hexavigesimal
utf
flutter-hooks
pygraphviz
apache-commons-dbutils
debugview
node-libcurl
fiddle
double
requestanimationframe
smooth-scrolling
spark-java
native-code
forcats
access-violation
vue-cli-4
suse
pomelo-entityframeworkcore-mysql
segment-tree
transform
excel-writer-xlsx
eslint
perforce-stream
phone-number
continuous-testing
keystore-access