z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
refined
itemprocessor
ruby-on-rails-6
inversion
hidden-field
moreutils
g1gc
cvxopt
itemssource
dllexport
itertools-groupby
pycall
shoes
assemblyversionattribute
flush
signalwire-api
latex-environment
hce
spring-io
takesscreenshot
torchaudio
sql-parametrized-query
memory-management
datastax-startup
denotational-semantics
anorm
azure-template
hana-sql-script
zizaco
openvswitch