'Clean up "Replica Sets" when updating deployments?

Every time a deployment gets updated, a new replica set is added to a long list. Should the old rs be cleaned?

kubernetes


Solution 1:[1]

Removing old replicasets is part of the Deployment object, but it is optional. You can set .spec.revisionHistoryLimit to tell the Deployment how many old replicasets to keep around.

Here is a YAML example:

apiVersion: apps/v1
kind: Deployment
# ...
spec:
  # ...
  revisionHistoryLimit: 0 # Default to 10 if not specified
  # ...

Solution 2:[2]

If you want to clean it manually you can just paste that in your console

kubectl delete $(kubectl get all | grep replicaset.apps | grep "0         0         0" | cut -d' ' -f 1)

This only works because of the way kubectl get all displays resources. It's a cheap solution but it's not that big an issue either.

Edit

Look at Joe Eaves's solution, it's similar but less dependent on the syntax (ignores white spaces at least)

Solution 3:[3]

A revision on Kévin's post above as I can't comment yet :D

AWK lets us ignore the spacing!

kubectl delete $(kubectl get all | grep replicaset.apps | awk '{if ($2 + $3 + $4 == 0) print $1}')

Solution 4:[4]

Here's a way to do it without AWK, using only kubectl and the built-in jsonpath functionality:

kubectl delete replicaset $(kubectl get replicaset -o jsonpath='{ .items[?(@.spec.replicas==0)].metadata.name }')

This should be more stable because it processes the replica count directly instead of trying to parse the output of kubectl which might change.

Solution 5:[5]

on k8s v1.19.6 i had to modify Joe Eaves' command as below to make it work:

kubectl -n <namespace> delete rs $(kubectl -n <namespace> get rs | awk '{if ($2 + $3 + $4 == 0) print $1}' | grep -v 'NAME')

Solution 6:[6]

A short way:

kubectl delete rs $(kubectl get rs | grep "0         0         0" | cut -d' ' -f 1)

Solution 7:[7]

One-Liner using awk and xargs deleting all ReplicaSets from all Namespaces:

kubectl get replicaset --all-namespaces -o=jsonpath='{range .items[?(@.spec.replicas==0)]}{.metadata.name}{"\t"}{.metadata.namespace}{"\n"}{end}' | awk '{print $1 " --namespace=" $2}' | xargs -n 2 -d '\n' bash -c 'kubectl delete replicaset $0 $1'

Solution 8:[8]

I do this way:

kubectl get replicasets.apps -n namespace | awk '{if ($2 + $3 + $4 == 0) print $1}' | xargs kubectl delete replicasets.apps -n namespace

first get all replicaset, then parse it with conditional and then, delete it.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Gian Marco
Solution 2 fearphage
Solution 3 Joe Eaves
Solution 4 Mike Matera
Solution 5 mkumar118
Solution 6 hejeroaz
Solution 7 Christian Knell
Solution 8 hiddenrebel

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