'Console/Symfony Call command from controller
I have some issues with Console when I try to call a Command from a Controller. I found a way in the Symfony CookBook : http://symfony.com/doc/current/cookbook/console/command_in_controller.html
It seems doesn't work... Maybe I forgot something!
Command :
namespace AppBundle\Command;
use Symfony\Component\Console\Command\Command;
use Symfony\Component\Console\Input\InputArgument;
use Symfony\Component\Console\Input\InputInterface;
use Symfony\Component\Console\Input\InputOption;
use Symfony\Component\Console\Output\OutputInterface;
class GreetCommand extends Command
{
protected function configure()
{
$this
->setName('demo:greet')
->setDescription('Greet someone')
->addArgument(
'name',
InputArgument::OPTIONAL,
'Who do you want to greet?'
)
->addOption(
'yell',
null,
InputOption::VALUE_NONE,
'If set, the task will yell in uppercase letters'
)
;
}
protected function execute(InputInterface $input, OutputInterface $output)
{
$name = $input->getArgument('name');
if ($name) {
$text = 'Hello '.$name;
} else {
$text = 'Hello';
}
if ($input->getOption('yell')) {
$text = strtoupper($text);
}
$output->writeln($text);
}
}
(The command works well in cmd)
Controller :
namespace AppBundle\Controller;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\Console\Application;
use Symfony\Component\Console\Input\ArrayInput;
use Symfony\Component\Console\Output\BufferedOutput;
class MainController extends Controller
{
public function indexAction()
{
$kernel = $this->get('kernel');
$application = new Application($kernel);
$application->setAutoExit(false);
$input = new ArrayInput(array(
'command' => 'demo:greet'
));
$output = new BufferedOutput();
$application->run($input, $output);
$content = $output->fetch();
dump($content);die;
}
}
Response
[Symfony\Component\Console\Exception\CommandNotFoundException] There are no commands defined in the "demo" namespace.
Thank you in advance for your help.
Solution 1:[1]
You used the wrong Application
. You should replace use Symfony\Component\Console\Application;
by use Symfony\Bundle\FrameworkBundle\Console\Application;
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Cyrille |