'Convert date-time string to class Date
I have a data frame with a character column of date-times.
When I use as.Date
, most of my strings are parsed correctly, except for a few instances. The example below will hopefully show you what is going on.
# my attempt to parse the string to Date -- uses the stringr package
prods.all$Date2 <- as.Date(str_sub(prods.all$Date, 1,
str_locate(prods.all$Date, " ")[1]-1),
"%m/%d/%Y")
# grab two rows to highlight my issue
temp <- prods.all[c(1925:1926), c(1,8)]
temp
# Date Date2
# 1925 10/9/2009 0:00:00 2009-10-09
# 1926 10/15/2009 0:00:00 0200-10-15
As you can see, the year of some of the dates is inaccurate. The pattern seems to occur when the day is double digit.
Any help you can provide will be greatly appreciated.
Solution 1:[1]
The easiest way is to use lubridate:
library(lubridate)
prods.all$Date2 <- mdy(prods.all$Date2)
This function automatically returns objects of class POSIXct
and will work with either factors or characters.
Solution 2:[2]
library(lubridate)
if your date format is like this '04/24/2017 05:35:00'then change it like below
prods.all$Date2<-gsub("/","-",prods.all$Date2)
then change the date format
parse_date_time(prods.all$Date2, orders="mdy hms")
Solution 3:[3]
If you don't know the format you could use anytime::anydate
, which tries to match to common formats:
library(anytime)
date <- c("01/01/2000 0:00:00", "Jan 1, 2000 0:00:00", "2000-Jan-01 0:00:00")
anydate(date)
[1] "2000-01-01" "2000-01-01" "2000-01-01"
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | hadley |
Solution 2 | Nayab khan |
Solution 3 | LMc |