'counting words inside a webpage

I need to count words that are inside a webpage using python3. Which module should I use? urllib?

Here is my Code:

def web():
    f =("urllib.request.urlopen("https://americancivilwar.com/north/lincoln.html")
    lu = f.read()
    print(lu)


Solution 1:[1]

With below self explained code you can get a good starting point for counting words within a web page:

import requests
from bs4 import BeautifulSoup
from collections import Counter
from string import punctuation

# We get the url
r = requests.get("https://en.wikiquote.org/wiki/Khalil_Gibran")
soup = BeautifulSoup(r.content)

# We get the words within paragrphs
text_p = (''.join(s.findAll(text=True))for s in soup.findAll('p'))
c_p = Counter((x.rstrip(punctuation).lower() for y in text_p for x in y.split()))

# We get the words within divs
text_div = (''.join(s.findAll(text=True))for s in soup.findAll('div'))
c_div = Counter((x.rstrip(punctuation).lower() for y in text_div for x in y.split()))

# We sum the two countesr and get a list with words count from most to less common
total = c_div + c_p
list_most_common_words = total.most_common() 

If you want for example the first 10 most common words you just do:

total.most_common(10)

Which in this case outputs:

In [100]: total.most_common(10)
Out[100]: 
[('the', 2097),
 ('and', 1651),
 ('of', 998),
 ('in', 625),
 ('i', 592),
 ('a', 529),
 ('to', 529),
 ('that', 426),
 ('is', 369),
 ('my', 365)]

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1