'Django 2.0: sqlite IntegrityError: FOREIGN KEY constraint failed

I'm working on adding Django 2.0 support to the django-pagetree library. During automated testing, using an sqlite in-memory database, I'm getting a bunch of errors like this:

  File "/home/nnyby/src/django-pagetree/pagetree/tests/test_models.py", line 638, in setUp
    'children': [],
  File "/home/nnyby/src/django-pagetree/pagetree/models.py", line 586, in add_child_section_from_dict

...

  File "/home/nnyby/src/django-pagetree/venv/lib/python3.5/site-packages/django/db/backends/base/base.py", line 239, in _commit
    return self.connection.commit()
django.db.utils.IntegrityError: FOREIGN KEY constraint failed

This is noted in the Django 2.0 release notes: https://docs.djangoproject.com/en/2.0/releases/2.0/#foreign-key-constraints-are-now-enabled-on-sqlite

From that description, which I don't fully understand, this shouldn't apply for test databases that aren't persistent, right? Wouldn't my sqlite test db get created with the appropriate options when using Django 2.0?

The app settings I'm using for testing are here: https://github.com/ccnmtl/django-pagetree/blob/master/runtests.py



Solution 1:[1]

The documentation says two things:

  1. If you have ForeignKey constraints they are now enforced at the database level. So make sure you're not violating a foreign key constraint. That's the most likely cause for your issue, although that would mean you'd have seen these issues with other databases. Look for patterns like this in your code:

    # in pagetree/models.py, line 810
    @classmethod
    def create_from_dict(cls, d):
        return cls.objects.create()  # what happens to d by the way?
    

    This will definitely fail with a ForeignKey constraint error since a PageBlock must have section, so you can't call create without first assigning it.

  2. If you circumvent the foreign key constraint by performing an atomic transaction (for example) to defer committing the foreign key, your Foreign Key needs to be INITIALLY DEFERRED. Indeed, your test db should already have that since it's rebuilt every time.

Solution 2:[2]

I met a different situation with the same error. The problem was that I used the same Model name and field name

Incorrect code:

class Column(models.Model):
    ...

class ColumnToDepartment(models.Model):
    column = models.ForeignKey(Column, on_delete=models.CASCADE)

Solution:

class Column(models.Model):
    ...

class ColumnToDepartment(models.Model):
    referring_column = models.ForeignKey(Column, on_delete=models.CASCADE)

Solution 3:[3]

Solution 4:[4]

In my case, i found that the ForeignKey object that my model refer to is not exist. So that i just change the referenced FK object to exist object.

Solution 5:[5]

I just had this error: sqlite3.IntegrityError: FOREIGN KEY constraint failed on my Django project. Turns out I deleted the migrations folder somewhere along the line so it didn't pick up my model changes when I ran python manage.py makemigrations. Just make sure you still have a migrations folder with migrations in.

Solution 6:[6]

One more thing to check, in my case it was related to my fixtures files. Regenerating them after migration to Django3 solved the issue I had while testing my app.

./manage.py dumpdata app.Model1 app.Model2 --indent=4 > ./app/fixtures/file.json

Solution 7:[7]

When I have trouble with migrations or tables, I do it and it very often helps:

  1. Comment your trouble strings;
  2. Do python3 manage.py makemigrations and python3 manage.py migrate;
  3. Then u must do python3 manage.py migrate --fake;
  4. Uncomment your strings and do it again python3 manage.py makemigrations and python3 manage.py migrate.

I hope it is useful for u

Solution 8:[8]

My problem was solved after doing the migration, because I have altered the foreign key and then didn't apply the migrations.

Specifically, at first I have the following piece of code in models:

class TeacherRequest(models.Model):
    requester = models.ForeignKey(
        Profile,
        on_delete=models.CASCADE,
        related_name="teacher_request",
    )

    class RequestStatus(models.TextChoices):
        PENDING = '1', _('pending')
        APPROVED = '2', _('approved')
        REJECTED = '3', _('rejected')

    status = models.CharField(
        choices=RequestStatus.choices,
        max_length=1,
        default=RequestStatus.PENDING,
    )

Then I have changed the foreign key from Profile to User:


class TeacherRequest(models.Model):
    requester = models.ForeignKey(
        User,
        on_delete=models.CASCADE,
        related_name="teacher_request",
    )

    class RequestStatus(models.TextChoices):
        PENDING = '1', _('pending')
        APPROVED = '2', _('approved')
        REJECTED = '3', _('rejected')

    status = models.CharField(
        choices=RequestStatus.choices,
        max_length=1,
        default=RequestStatus.PENDING,
    )

Solution

python manage.py makemigrations
python manage.py migrate

Solution 9:[9]

A reason could be you miscalculated what happens when you delete an item from the db that is linked with a foreign key to something else, elsewhere.

p.e. what happens when you delete an author that has active books?

I don't meant to enter into the logic of the application, but consider for example to cascade the deletion of the elements linked to that key.

Here is an example, in this case we are dealing with "post" attribute for each "user"

user = models.ForeignKey(User, related_name='posts', on_delete=models.CASCADE)

Here's a careful explanation, Django 4.0: https://docs.djangoproject.com/en/4.0/ref/models/fields/

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 dirkgroten
Solution 2 Eric Jin
Solution 3 Krzysieqq
Solution 4 Lê Hoàng V?
Solution 5 Bennie van Eeden
Solution 6 Theo Godard
Solution 7 Michael Adams
Solution 8 Mostafa Ghadimi
Solution 9 Carlo