'function which tells whether an array is subsequence of another but 1 of the loop isnt working
def is_subsequence_array(array, sequence):
for num in sequence:
if array.count(num) != 1 :
output = False
for i in range(len(sequence) - 1):
if array.index(sequence[i + 1]) < array.index(sequence[i]):
output = False
else:
output = True
return(output)
print(is_subsequence_array([5, 6, 3], [2, 1]))
Solution 1:[1]
I think this should work:
def is_subsequence_array(array, sequence):
for index, num in enumerate(array):
if num == sequence[0] and len(array) - index >= len(sequence):
output = True
for i in range(len(sequence) - 1):
if array[index + i] != sequence[i]:
output = False
break
if output:
return True
return False
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Dmytro Kolupaiev |