Get query string as function parameters on flask

Question

Is there a way to get query string as function parameters on flask?
For example, the request will be like this.

http://localhost:5000/user?age=15&gender=Male

And hope the code similar to this.

@app.route("/user")
def getUser(age, gender):
...

Answer 1

If you are willing to write a decorator, anything is possible:

from functools import wraps

def extract_args(*names, **names_and_processors):
    user_args = ([{"key": name} for name in names] +
        [{"key": key, "type": processor}
            for (key, processor) in names_and_processors.items()])

    def decorator(f):
        @wraps(f)
        def wrapper(*args, **kwargs):
            final_args, final_kwargs = args_from_request(user_args, args, kwargs)
            return f(*final_args, **final_kwargs)
        return wrapper
    return decorator if len(names) < 1 or not callable(names[0]) else decorator(names[0])

def args_from_request(to_extract, provided_args, provided_kwargs):
    # Ignoring provided_* here - ideally, you'd merge them
    # in whatever way makes the most sense for your application
    results = {}
    for arg in to_extract:
        result[arg["key"]] = request.args.get(**arg)
    return provided_args, results

Usage:

@app.route("/somewhere")
@extract_args("gender", age=int)
def somewhere(gender, age):
    return jsonify(gender=gender, age=age)

Answer 2

Flask views themselves do not have obligatory args. You can write:

from flask import request

@app.route("/user")
def getUser():
    age = request.args.get('age')
    gender = request.args.get('gender')

Answer 3

You can do this by getting Flask-Publisher and adding "@publish()" decorator before your getUser function:

from publisher import publish

@app.route("/user")
@publish()
def getUser(age:int, gender):
...

This uses inspection to get the arguments, optionally uses type annotations to convert the incoming arguments, and pulls the values from the GET/POST data.