'How to get entire line that contains given string using findstr in batch script?
I need to get the line that contains the keyword ProductVersion
from one of my svn repository csproj
files. I have tried below code, but it is not working as expected.
The batch file is:
@echo off
setlocal enabledelayedexpansion
rem https://testur/test.csproj
for %%t in (%*) do (
rem echo url: %%t
for /f "tokens=1" %%c in ('svn cat %%t ^| findstr /i ProductVersion') do (
echo output: %%c
)
)
csproj
file content:
<VisualStudioProject>
<CSHARP
ProjectType = "Local"
ProductVersion = "7.10.3077"
Schemaversion = "2.0"
Here the url is passed as command line argument to the batch file. The ProductVersion
line in csproj
file also contains =
and some spaces. svn cat %%t
would return me the content of file test.csproj
. I am applying findstr
on the received file content. When I tried with above code it returns only ProductVersion
without the remaining string "7.0.3077"
as output.
How to get the ProductVerion
value 7.0.3077
or the entire line?
Sources
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Source: Stack Overflow
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